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EXAMPLE 3<br />

More on solving a consistent system of equations<br />

Determine the solution to the following system of equations:<br />

1<br />

2<br />

3<br />

2x y z 1<br />

4x y z 5<br />

8x 2y 2z 10<br />

Solution<br />

Again, using elementary operations,<br />

1<br />

4<br />

5<br />

2x y z 1<br />

0x 3y 3z 3<br />

0x 6y 6z 6<br />

2 <br />

4 <br />

1<br />

1<br />

<br />

<br />

2<br />

3<br />

Continuing, we obtain<br />

1<br />

2x y z 1<br />

4<br />

0x 3y 3z 3<br />

6<br />

0x 0y 0z 0<br />

2 <br />

4<br />

<br />

5<br />

Equation<br />

6<br />

indicates that this system has an infinite number of solutions.<br />

We can solve this system by using a parameter for either y or z.<br />

Substituting y s in equation 4 gives 3s 3z 3 or z s 1.<br />

Substituting into equation 1 , 2x s 1s 12 1 or x 1.<br />

Therefore, the solution to this system is x 1, y s, and z s 1, sR.<br />

Check:<br />

Substituting into equation 1 , 2112 s 1s 12 2 s s 1 1.<br />

Substituting into equation 2 , 4112 s 1s 12 4 s s 1 5.<br />

There is no need to check in our third equation since 2 <br />

represents the same plane as equation 2 .<br />

2<br />

<br />

3<br />

. Equation<br />

3<br />

!<br />

It is worth noting that the normals of the second and third planes, n<br />

! 2 14, 1, 12<br />

and n 3 18, 2, 22, are scalar multiples of each other, and that the constants on<br />

the right-hand side are related by the same factor. This indicates that the two<br />

equations represent the same plane. Since neither of these normals and the first<br />

!<br />

plane’s normal n 1 12, 1, 12 are scalar multiples of each other, the first plane must<br />

intersect the two coincident planes along a line passing through the point<br />

with direction vector m ! 11, 0, 12<br />

10, 1, 12. This corresponds to Case 2b.<br />

NEL<br />

CHAPTER 9 525

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