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INVESTIGATION<br />

Here is an alternate technique for finding the value of a limit.<br />

1x 12<br />

A. Find lim by rationalizing.<br />

xS1 x 1<br />

1x 12<br />

B. Let u Vx, and rewrite lim in terms of u. We know x u 2 , Vx 0,<br />

xS1 x 1<br />

and u 0. Therefore, as x approaches the value of 1, u approaches the value of 1.<br />

1u<br />

Use this substitution to find<br />

2 12<br />

by reducing the rational expression.<br />

u 1<br />

lim<br />

uS1<br />

EXAMPLE 7<br />

Selecting a substitution strategy to evaluate a limit<br />

Evaluate<br />

lim<br />

xS0<br />

1x 82 1 3 2<br />

.<br />

x<br />

Solution<br />

This quotient is indeterminate Q 0 when x 0. Rationalizing the numerator<br />

0 R<br />

1<br />

3<br />

1x 82 2 is not so easy. However, the expression can be simplified by<br />

substitution. Let u 1x 82 1 3 . Then u 3 x 8 and x u 3 8. As x<br />

approaches the value 0, u approaches the value 2. The given limit becomes<br />

1x 82 1 3 2<br />

lim<br />

lim<br />

xS0 x<br />

uS2<br />

lim<br />

uS2<br />

lim<br />

uS2<br />

u 2<br />

u 3 8<br />

1<br />

u 2<br />

1u 221u 2 2u 42<br />

u 2 2u 4<br />

(Factor)<br />

(Simplify)<br />

(Evaluate)<br />

1 12<br />

EXAMPLE 8<br />

Evaluating a limit that involves absolute value<br />

0 x 2 0<br />

Evaluate lim Illustrate with a graph.<br />

xS2<br />

x 2 .<br />

Solution<br />

Consider the following:<br />

1x 22<br />

f 1x2 0 x 2 0<br />

x 2 µ x 2 ,if x 7 2<br />

1x 22<br />

x 2 , if x 6 2<br />

1, if x 7 2<br />

e<br />

1, if x 6 2<br />

NEL CHAPTER 1 43

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