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Review Exercise, pp. 56–59<br />

1. a. 3 b. 7<br />

c. 2x y 5 0<br />

2. a.<br />

1<br />

3<br />

c. 1 27<br />

b.<br />

1<br />

2<br />

d. 5 4<br />

3. a. 2 b. 2<br />

4. a. 1st second 5 ms, ><br />

2nd second 15 ms ><br />

b. 40 ms ><br />

c. 60 ms ><br />

5. a. 0.0601 g<br />

b. 6.01 g><br />

min<br />

c. 6 g><br />

min<br />

6. a. 700 000 t<br />

b. 18 10 4 t per year<br />

c. 15 10 4 t per year<br />

d. 7.5 years<br />

7. a. 10<br />

b. 7; 0<br />

c. t 3 and t 4<br />

8. a. Answers may vary. For example:<br />

–2<br />

2<br />

1<br />

b. Answers may vary. For example:<br />

4<br />

2<br />

y<br />

x<br />

–1 0 1 2<br />

–1<br />

–2<br />

y<br />

9. a.<br />

b. x 1 and x 1<br />

c. They do not exist.<br />

10. not continuous at x 4<br />

11. a. x 1 and x 2<br />

b. lim f 1x2 2 ,<br />

xS1 3<br />

lim f 1x2 does not exist.<br />

xS2<br />

12. a. lim f 1x2 does not exist.<br />

xS0<br />

b. lim g1x2 0<br />

xS0<br />

c. lim h1x2 does not exist.<br />

xS3<br />

13. a.<br />

x 1.9 1.99 1.999 2.001 2.01 2.1<br />

x 2<br />

x 2 x 2<br />

14.<br />

–4 –2<br />

b.<br />

1<br />

3<br />

1<br />

2<br />

4<br />

2<br />

y<br />

x<br />

0 2 4<br />

–2<br />

–4<br />

0<br />

16. a. 10 b.<br />

1<br />

c. 1<br />

4 16<br />

17. a. 4 c.<br />

1<br />

5<br />

e. 1 8<br />

b. 10a d.<br />

1<br />

3<br />

f. 1 4<br />

18. a. The function is not defined for<br />

x 6 3, so there is no left-side limit.<br />

b. Even after dividing out common<br />

factors from numerator and<br />

denominator, there is a factor of<br />

x 2 in the denominator; the graph<br />

has a vertical asymptote at x 2.<br />

c. lim<br />

xS1f 1x2 5 lim xS1 <br />

d. The function has a vertical<br />

asymptote at x 2.<br />

e. x S 0 0x x<br />

0x 0<br />

lim<br />

xS0 x 1<br />

0x 0<br />

lim<br />

xS0 x 1<br />

0x 0<br />

lim<br />

xS0 x lim 0x 0<br />

xS0 x<br />

0.344 83 0.334 45 0.333 44 0.333 22 0.332 23 0.322 58<br />

x 0.9 0.99 0.999 1.001 1.01 1.1<br />

x 1<br />

x 2 1<br />

0.526 32 0.502 51 0.500 25 0.499 75 0.497 51 0.476 19<br />

x 0.1 0.01 0.001 0.001 0.01 0.1<br />

–4 –2<br />

x<br />

0 2 4<br />

–2<br />

–4<br />

x 3 3<br />

x<br />

0.291 12 0.288 92 0.2887 0.288 65 0.288 43 0.286 31<br />

1<br />

; This agrees well with the values<br />

23<br />

in the table.<br />

15. a.<br />

x 2.1 2.01 2.001 2.0001<br />

f(x) 0.248 46 0.249 84 0.249 98 0.25<br />

lim f 1x2 0.25<br />

xS2<br />

b. lim f 1x2 0.25<br />

xS2<br />

c. 0.25<br />

f.<br />

lim f 1x2 1<br />

xS1 <br />

f 1x2 5<br />

lim<br />

xS1 <br />

lim<br />

xS1 <br />

f 1x2 <br />

Therefore, lim f 1x2 does not exist.<br />

xS1<br />

lim<br />

xS1 <br />

f 1x2<br />

628 Answers<br />

NEL

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