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Both of these vectors can be multiplied by 4 to ensure that both direction numbers<br />

are integers. As a result, either m ! 11, 142 or m ! 11, 142 are the best choices<br />

for a direction vector. When we determine the direction vector, any scalar multiple of<br />

this vector of the form t11, 142 is correct, provided that t 0. If t 0, 10, 02 would<br />

be the direction vector, meaning that the line would not have a defined direction.<br />

Expressing the Equations of Lines Using Vectors<br />

In general, we would like to determine the equation of a line if we have a<br />

direction for the line and a point on it. In the following diagram, the given point<br />

!<br />

P 0 1x 0 , y 0 2 is on the line L and is associated with vector OP<br />

!0, designated as<br />

The direction of the line is given by where is any vector<br />

collinear with m ! m ! tm ! r 0 .<br />

1a, b2, , tR<br />

. P1x, y2 represents a general point on the line, where OP !<br />

is the<br />

vector associated with this point.<br />

O<br />

y<br />

r = r 0 + tm, t P R<br />

L<br />

P tm<br />

0 (x 0 , y 0 ) P(x, y)<br />

r r 0<br />

m = (a, b)<br />

To find the vector equation of line L, the triangle law of addition is used.<br />

In OP ! !<br />

^OP OP 0 P0 P ! 0 P,<br />

.<br />

x<br />

! ! ! !<br />

Since and the vector equation of the line is<br />

written as r ! tm ! P<br />

! ! 0 P ! r OP , r 0 OP0 ,<br />

,<br />

r 0 tm , tR.<br />

When writing an equation of a line using vectors, the vector form of the line is<br />

sometimes modified and put in parametric form. The parametric equations of a<br />

line come directly from its vector equation. How to change the equation of a line<br />

from vector to parametric form is shown below.<br />

The general vector equation of a line is r ! ! !<br />

r 0 tm , tR.<br />

In component form, this is written as 1x, y2 1x 0 , y 0 2 t1a, b2, tR. Expanding<br />

the right side, 1x, y2 1x 0 , y 0 2 1ta, tb2 1x 0 ta, y 0 tb2, tR. If we equate<br />

the respective x and y components, the required parametric form is x x 0 ta<br />

and y y 0 tb, tR.<br />

Vector and Parametric Equations of a Line in R 2<br />

Vector Equation: r ! ! !<br />

r 0 tm , tR<br />

Parametric Equations: x x<br />

!<br />

0 ta, y y 0 tb, tR<br />

where r is the vector from 10, 02 to the point 1x and m !<br />

0 0 , y 0 2 is a direction<br />

vector with components 1a, b2.<br />

428<br />

8.1 VECTOR AND PARAMETRIC EQUATIONS OF A LINE IN R 2<br />

NEL

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