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Determine any asymptotes.<br />

The function is not defined if<br />

x 2 x 2 0<br />

1x 221x 12 0<br />

x 2 and x 1<br />

The domain is 5xR 0 x 2 and x 16.<br />

There are vertical asymptotes at x 2 and x 1.<br />

Using f 1x2 x 4 we examine function values near the asymptotes.<br />

x 2 x 2 ,<br />

lim<br />

xS1 <br />

lim<br />

xS2 <br />

f 1x2 q<br />

f 1x2 q<br />

Sketch the information you have so far, as shown.<br />

y<br />

4<br />

x = –1 x = 2<br />

3<br />

2<br />

(0, 2)<br />

1<br />

(4, 0) x<br />

–2 –1 0<br />

–1<br />

1 2 3 4<br />

–2<br />

lim f 1x2 q<br />

xS1 <br />

lim<br />

xS2 <br />

f 1x2 q<br />

Analyze f ¿(x). Now determine the critical points.<br />

f 1x2 1x 421x 2 x 22 1<br />

f ¿1x2 1121x 2 x 22 1 1x 421121x 2 x 22 2 12x 12<br />

1<br />

<br />

x 2 x 2<br />

1x2 x 22<br />

1x 2 x 22 2 12x2 9x 42<br />

1x 2 x 22 2<br />

x2 8x 6<br />

1x 2 x 22 2<br />

f ¿1x2 0 if x 2 8x 6 0<br />

x 8 ; 210<br />

2<br />

x 4 ; 10<br />

<br />

1x 4212x 12<br />

1x 2 x 22 2<br />

Since we are sketching, approximate values 7.2 and 0.8 are acceptable. These<br />

values give the approximate points 17.2, 0.12 and 10.8, 1.52.<br />

210 4.5 AN ALGORITHM FOR CURVE SKETCHING<br />

NEL

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