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Calculus- Early Transcendentals, 2021a

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226 Integration<br />

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Figure 6.9: General Riemann sum to approximate the area under f (x)=4x − x 2 .<br />

Figure 6.9 shows the approximating rectangles of a Riemann sum. While the rectangles in this example<br />

do not approximate well the shaded area, they demonstrate that the subinterval widths may vary and the<br />

heights of the rectangles can be determined without following a particular rule.<br />

Riemann sums are typically calculated using one of the three rules we have introduced. The uniformity<br />

of construction makes computations easier. Before working another example, let’s summarize some of<br />

what we have learned in a convenient way.<br />

Riemann Sums<br />

Consider a function f (x) defined on an interval [a,b]. The area under this curve is approximated by<br />

∑ n i=1 f (c i)Δx i .<br />

1. When the n subintervals have equal length, Δx i = Δx = b − a<br />

n .<br />

2. The i th term of the partition is x i = a +(i − 1)Δx. (Thismakesx n+1 = b.)<br />

n<br />

3. The Left Hand Rule summation is: ∑ f (x i )Δx.<br />

i=1<br />

4. The Right Hand Rule summation is:<br />

5. The Midpoint Rule summation is:<br />

n<br />

∑ f (x i+1 )Δx.<br />

i=1<br />

(<br />

xi + x x+1<br />

n<br />

∑ f<br />

i=1<br />

2<br />

)<br />

Δx.<br />

Let’s do another example.<br />

Example 6.9: Approximating Area Using Sums<br />

Approximate the area under f (x)=(5x +2) on the interval [−2,3] using the Midpoint Rule and ten<br />

equally spaced intervals.<br />

Solution. Following the above discussion, we have<br />

Δx = 3 − (−2) = 1/2<br />

10

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