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Calculus- Early Transcendentals, 2021a

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240 Integration<br />

n<br />

( ) 2i 2<br />

= lim n→∞ ∑ f<br />

i=1<br />

n n<br />

n<br />

( ) 2i 2<br />

= lim<br />

n→∞<br />

∑<br />

i=1<br />

n + 1 n<br />

( 4i<br />

n 2 + 2 )<br />

n<br />

= lim<br />

n→∞<br />

n<br />

∑<br />

i=1<br />

= lim<br />

= lim<br />

n→∞<br />

( n∑<br />

i=1<br />

n→∞<br />

(<br />

n<br />

4i<br />

n 2 + ∑<br />

i=1<br />

n<br />

4<br />

n ∑ 2 +<br />

i=1i 2 n<br />

)<br />

2<br />

n<br />

n<br />

∑<br />

i=1<br />

1<br />

)<br />

( 4 n(n + 1)<br />

= lim<br />

n→∞ n 2 + 2 )<br />

2 n n<br />

(<br />

= lim 2 + 2 )<br />

n→∞ n + 2<br />

= 4.<br />

3. Finally, let’s evaluate the net area under x + 1 from 0 to 2.<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

Thus, the area is the sum of the areas of a rectangle and a triangle. Hence,<br />

∫ 2<br />

0<br />

x + 1 dx = Net Area<br />

= Area of rectangle + Area of triangle<br />

= (2)(1)+ 1 2 (2)(2)<br />

= 4.<br />

♣<br />

We next apply FTC to differentiate a function.

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