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Calculus- Early Transcendentals, 2021a

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9.1. Sequences 339<br />

log 2 (1 + ε) > 1 n<br />

1 + ε > 2 1/n<br />

ε > 2 1/n − 1<br />

∣<br />

ε > ∣2 1/n − 1∣<br />

Note that we generally need to work “backwards” from the last line of the proof to determine how to<br />

choose N. Having done so, we write the actual proof as we have done here to show that this value of N<br />

‘works’.<br />

If a sequence is defined by a formula { f (i)} ∞ i=1 , we can often expand the domain of the function f to<br />

the set of all (or almost all) real numbers. For example, f (i)= 1 i<br />

is defined for all non-zero real numbers.<br />

When this happens, we can sometimes find the limit of the sequence { f (i)} ∞ i=1<br />

more easily by finding<br />

the limit of the function f (x), x ∈ R, asx approaches infinity.<br />

Theorem 9.3: Limit of a Sequence<br />

If lim x→∞ f (x)=L, where f : R → R, then{ f (i)} ∞ i=1<br />

converges to L.<br />

♣<br />

Proof. This follows immediately from earlier definitions and 9.1.<br />

♣<br />

Hereafter we will use the convention that x refers to a real-valued variable and i and n are integervalued.<br />

Example 9.4: Sequence of 1/n<br />

Show that { 1 n }∞ n=0<br />

converges to 0.<br />

Solution. Since lim x→∞<br />

1<br />

x<br />

= 0, lim n→∞<br />

1<br />

n<br />

= 0.<br />

♣<br />

Note that the converse of Theorem 9.3 is not true.<br />

Let f (n)=sin(nπ). This is the sequence<br />

sin(0π),sin(1π),sin(2π),sin(3π),...= 0,0,0,0,...<br />

since sin(nπ)=0whenn is an integer. Thus lim f (n)=0. But lim f (x), whenx is real, does not exist:<br />

n→∞ x→∞<br />

as x gets bigger and bigger, the values sin(xπ) do not get closer and closer to a single value, but take on<br />

all values between −1 and 1 over and over. In general, whenever you want to know lim f (n) you should<br />

n→∞<br />

first attempt to compute lim f (x), since if the latter exists it is also equal to the first limit. But if for some<br />

x→∞<br />

reason lim f (x) does not exist, it may still be true that lim f (n) exists, but you’ll have to figure out another<br />

x→∞ n→∞<br />

way to compute it.<br />

It is occasionally useful to think of the graph of a sequence. Since the function is defined only for<br />

integer values, the graph is just a sequence of points. In Figure 9.1 we see the graphs of two sequences<br />

and the graphs of the corresponding real functions.

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