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Calculus- Early Transcendentals, 2021a

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∫<br />

du<br />

108.<br />

u √ a + bu = √ 1<br />

√ √ ∣ ln<br />

a + bu − a∣∣∣<br />

a ∣√ √ +C,if a > 0,<br />

a + bu + a<br />

= √ 2<br />

√<br />

a + bu<br />

tan −1<br />

−a −a +C,if a < 0<br />

∫ √<br />

a + bu<br />

109.<br />

du = 2 √ ∫<br />

du<br />

a + bu + a<br />

u<br />

u √ a + bu<br />

∫ √ √<br />

a + bu a + bu<br />

110.<br />

u 2 du = − + b ∫<br />

du<br />

u 2 u √ a + bu<br />

∫<br />

111. u n√ [<br />

∫<br />

2<br />

a + bu du = u n (a + bu) 3/2 − na u n−1√ ]<br />

a + bu du<br />

b(2n + 3)<br />

112.<br />

113.<br />

∫<br />

∫<br />

u n du<br />

√ = 2un√ a + bu<br />

a + bu b(2n + 1) − 2na ∫<br />

b(2n + 1)<br />

√<br />

du<br />

a + bu<br />

u n√ a + bu = −<br />

b(2n − 3)<br />

−<br />

a(n − 1)un−1 2a(n − 1)<br />

u n−1 du<br />

√<br />

a + bu<br />

∫<br />

du<br />

u n−1√ a + bu<br />

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