06.09.2021 Views

Calculus- Early Transcendentals, 2021a

Calculus- Early Transcendentals, 2021a

Calculus- Early Transcendentals, 2021a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

474 Partial Differentiation<br />

Exercise 13.6.10 Let α and k be constants. Prove that the function u(x,t)=e −α2 k 2t sin(kx) is a solution<br />

to the heat equation u t = α 2 u xx .<br />

Exercise 13.6.11 Let a be a constant. Prove that u = sin(x − at)+ln(x + at) is a solution to the wave<br />

equation u tt = a 2 u xx .<br />

Exercise 13.6.12 How many third-order derivatives does a function of 2 variables have? How many of<br />

these are distinct?<br />

Exercise 13.6.13 How many nth order derivatives does a function of 2 variables have? How many of<br />

these are distinct?<br />

13.7 Maxima and Minima<br />

Suppose a surface given by f (x,y) has a local maximum at (x 0 ,y 0 ,z 0 ); geometrically, this point on the<br />

surface looks like the top of a hill. If we look at the cross-section in the plane y = y 0 , we will see a local<br />

maximum on the curve at (x 0 ,z 0 ), and we know from single-variable calculus that ∂z<br />

∂x<br />

= 0 at this point.<br />

Likewise, in the plane x = x 0 , ∂z<br />

∂y = 0. So if there is a local maximum at (x 0,y 0 ,z 0 ), both partial derivatives<br />

at the point must be zero, and likewise for a local minimum. Thus, to find local maximum and minimum<br />

points, we need only consider those points at which both partial derivatives are 0. As in the single-variable<br />

case, it is possible for the derivatives to be 0 at a point that is neither a maximum or a minimum, so we<br />

need to test these points further.<br />

You will recall that in the single variable case, we examined three methods to identify maximum<br />

and minimum points; the most useful is the second derivative test, though it does not always work. For<br />

functions of two variables there is also a second derivative test; again it is by far the most useful test,<br />

though it doesn’t always work.<br />

Theorem 13.25: Extrema Test for Multivariate Functions<br />

Suppose that the second partial derivatives of f (x,y) are continuous near (x 0 ,y 0 ),and f x (x 0 ,y 0 )=<br />

f y (x 0 ,y 0 )=0. WedenotebyD the discriminant D(x 0 ,y 0 )= f xx (x 0 ,y 0 ) f yy (x 0 ,y 0 ) − f xy (x 0 ,y 0 ) 2 .If<br />

D > 0 and f xx (x 0 ,y 0 ) < 0 there is a local maximum at (x 0 ,y 0 );ifD > 0 and f xx (x 0 ,y 0 ) > 0 there is a<br />

local minimum at (x 0 ,y 0 );ifD < 0 there is neither a maximum nor a minimum at (x 0 ,y 0 );ifD = 0,<br />

the test fails.<br />

Example 13.26: Extrema on an Elliptic Paraboloid<br />

Verify that f (x,y)=x 2 + y 2 has a minimum at (0,0).<br />

Solution. First, we compute all the needed derivatives:<br />

f x = 2x f y = 2y f xx = 2 f yy = 2 f xy = 0.<br />

The derivatives f x and f y are zero only at (0,0). Applying the second derivative test there:<br />

D(0,0)= f xx (0,0) f yy (0,0) − f xy (0,0) 2 = 2 · 2 − 0 = 4 > 0,

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!