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Calculus- Early Transcendentals, 2021a

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12 Review<br />

Guidelines for Solving Rational Inequalities<br />

1. Move everything to one side to get a 0 on the other side.<br />

2. If needed, combine terms using a common denominator.<br />

3. Factor the numerator and denominator.<br />

4. Identify points where either the numerator or denominator is 0. Such points are called split<br />

points.<br />

5. Draw a number line and indicate your split points on the number line. Draw closed/open<br />

circles for each split point depending on if that split point satisfies the inequality (division by<br />

zero is not allowed).<br />

6. The split points will split the number line into subintervals. For each subinterval pick a test<br />

point and see if the expression in Step 3 is positive or negative. Indicate this with a + or −<br />

symbol on the number line for that subinterval.<br />

7. Now write your answer in set-builder notation. Use the union symbol ∪ if you have multiple<br />

intervals in your solution.<br />

Example 1.13: Rational Inequality<br />

Write the solution to the following inequality using interval notation:<br />

2 − x<br />

2 + x ≥ 1.<br />

Solution. One method to solve this inequality is to multiply both sides by 2 + x, but because we do not<br />

know if 2+x is positive or negative we must split it into two cases (Case 1: 2+x > 0 and Case 2: 2+x < 0).<br />

Instead we follow the guidelines for solving rational inequalities:<br />

Start with original problem:<br />

Move everything to one side:<br />

Find a common denominator:<br />

Combine fractions:<br />

Expand numerator:<br />

Simplify numerator:<br />

2 − x<br />

2 + x ≥ 1<br />

2 − x<br />

2 + x − 1 ≥ 0<br />

2 − x<br />

2 + x − 2 + x<br />

2 + x ≥ 0<br />

(2 − x) − (2 + x)<br />

2 + x<br />

2 − x − 2 − x<br />

2 + x<br />

≥ 0<br />

−2x<br />

2 + x ≥ 0 (∗)<br />

≥ 0

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