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Calculus- Early Transcendentals, 2021a

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542 Vector <strong>Calculus</strong><br />

Example 16.8: Work Done<br />

Suppose an object moves from (−1,1) to (2,4) along the path r(t) =〈t,t 2 〉, subject to the force<br />

F = 〈xsiny,y〉. Find the work done.<br />

Solution. We can write the force in terms of t as 〈t sin(t 2 ),t 2 〉, and compute r ′ (t)=〈1,2t〉, and then the<br />

work is ∫ 2<br />

〈t sin(t 2 ),t 2 〉·〈1,2t〉dt =<br />

−1<br />

Alternately, we might write<br />

∫<br />

C<br />

getting the same answer.<br />

∫ 2<br />

−1<br />

t sin(t 2 )+2t 3 dt =<br />

cos(1) − cos(4)<br />

2<br />

+ 15<br />

2 .<br />

∫ ∫ 2<br />

∫ 4<br />

xsinydx+ ydy= xsin(x 2 )dx+ ydy= − cos(4) + cos(1) + 16<br />

C −1<br />

1<br />

2 2 2 − 1 2<br />

♣<br />

Exercises for 16.3.2<br />

∫<br />

Exercise 16.3.1 Compute<br />

Exercise 16.3.2 Compute<br />

Exercise 16.3.3 Compute<br />

Exercise 16.3.4 Compute<br />

Exercise 16.3.5 Compute<br />

Exercise 16.3.6 Compute<br />

Exercise 16.3.7 Compute<br />

Exercise 16.3.8 Compute<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

∫<br />

C<br />

xy 2 ds along the line segment from (1,2,0) to (2,1,3).<br />

sinxds along the line segment from (−1,2,1) to (1,2,5).<br />

zcos(xy)ds along the line segment from (1,0,1) to (2,2,3).<br />

∫<br />

xe y dx+ x 2 ydy along the line segment y = 3, 0 ≤ x ≤ 2.<br />

C<br />

∫<br />

xe y dx+ x 2 ydy along the line segment x = 4, 0 ≤ y ≤ 4.<br />

C<br />

∫<br />

xe y dx+ x 2 ydy along the curve x = 3t, y = t 2 , 0 ≤ t ≤ 1.<br />

C<br />

∫<br />

xe y dx+ x 2 ydy along the curve 〈e t ,e t 〉, −1 ≤ t ≤ 1.<br />

C<br />

〈cosx,siny〉·dr along the curve 〈t,t〉, 0 ≤ t ≤ 1.<br />

∫<br />

Exercise 16.3.9 Compute 〈1/xy,1/(x+y)〉·dr along the path from (1,1) to (3,1) to (3,6) using straight<br />

C<br />

line segments.<br />

∫<br />

Exercise 16.3.10 Compute 〈1/xy,1/(x + y)〉·dr along the curve 〈2t,5t〉, 1 ≤ t ≤ 4.<br />

C

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