15.02.2013 Views

reverse engineering – recent advances and applications - OpenLibra

reverse engineering – recent advances and applications - OpenLibra

reverse engineering – recent advances and applications - OpenLibra

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

252 Reverse Engineering <strong>–</strong> Recent Advances <strong>and</strong> Applications<br />

10 Will-be-set-by-IN-TECH<br />

0 1<br />

Fig. 5. Exemplary hierarchical bifurcating tree of depth n = 3.<br />

ν σ,k = 1 −<br />

wherein the sum, s σ,k, is given by<br />

2<br />

2<br />

4<br />

4<br />

3<br />

3<br />

3<br />

3<br />

4<br />

4<br />

[1 + (d + 1) σ]sσ,k + 1/2<br />

�<br />

[1 + (d + 1) σ]sσ,k + 1/2 � , (19)<br />

2<br />

− s2 σ,k<br />

sσ,k = 1<br />

k−1<br />

2k ∑ [1 + (d − 1) σ − cos (2πj/k)]<br />

j=0<br />

−1 . (20)<br />

Equations 16 through 20 give the concentrations in a single duct near its ends. In the following<br />

sections this result is extended to describe the oxygen currents crossing the exchange surface<br />

of alveolar membranes lining these ducts.<br />

4.1.2 Building the tree from a single branch<br />

A treelike structure can be assembled from the individually modeled branches of the previous<br />

section, <strong>and</strong> Fig. 5 illustrates of an exemplary bifurcating tree. Its branching hierarchy is<br />

conceptualized by parent <strong>and</strong> daughter branches, in which m-many daughter branches extend<br />

from each parent branch at the branch points. In this model, the branches are subscripted<br />

according to whether they are an entrance or exit quantity of a branch in a given generation,<br />

i.e. c ent,i is the entrance concentration of a branch in the i th generation along any path from<br />

leaf to root. The problem, then, is to compute the current, I, leaving the surface of the entire<br />

tree, which is the sum of the contributions from each individual branch, I i = I ent,i − I ext,i:<br />

I =<br />

n<br />

∑ m<br />

k=0<br />

k � � n<br />

Ient,k − Iext,k + m Iext,n = Ient,0, (21)<br />

wherein we have used I ext,k−1 = mI end,k . From Eqn. 21, we only need compute the current<br />

entering the tree by its root to find the current leaving the effective area of the reactive surface.<br />

A branch-by-branch renormalization procedure is now used to calculate this quantity.<br />

4<br />

4<br />

4<br />

4

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!