Sol Cap 02 - Edicion 8

COSMOS: Complete Online Solutions Manual Organization System
Chapter 2, Solution 133.
Free-Body Diagram
First, consider the sum of forces in the x-direction because there is only one unknown force:
or
Now
or
( ) ( )
Σ F = 0: T cos32° − cos42° − 20 kN cos 42° = 0
x
ACB
0.104903T ACB = 14.8629 kN
T ACB = 141.682 kN
( ) ( )
Σ F = 0: T sin 42°− sin 32° + 20 kN sin 42°− W = 0
y
ACB
( )( ) ( )( )
141.682 kN 0.139211 + 20 kN 0.66913 − W = 0
(b)
T = 141.7 kN !
(a)
ACB
W = 33.1 kN !
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell
© 2007 The McGraw-Hill Companies.