Sol Cap 02 - Edicion 8

COSMOS: Complete Online Solutions Manual Organization System
Chapter 2, Solution 17.
γ = 180° − 25° − 50°
γ = 105°
Using the Law of Cosines:
or
2
2 2
( ) ( ) ( )( )
R = 5 kN + 8 kN − 2 5 kN 8 kN cos105°
R = 10.4740 kN
Using the Law of Sines:
10.4740 kN 8 kN
=
sin105°
sin β
or β = 47.542°
and α = 47.542°− 25°
α = 22.542°
R = 10.47 kN 22.5° "
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell
© 2007 The McGraw-Hill Companies.