Sol Cap 02 - Edicion 8

COSMOS: Complete Online Solutions Manual Organization System
Chapter 2, Solution 134.
Free-Body Diagram: Pulley A
Σ F = 0: 2Psin 25° − Pcosα
= 0
x
and
cosα
= 0.8452 or α = ± 32.3°
For α =+ 32.3°
Σ F = 0: 2Pcos 25°+ Psin 32.3°− 350 lb = 0
y
or
P = 149.1 lb 32.3° ⊳
For α =− 32.3°
Σ F = 0: 2Pcos 25° + Psin − 32.3° − 350 lb = 0
y
or
P = 274 lb 32.3° ⊳
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell
© 2007 The McGraw-Hill Companies.