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7 months ago

Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 8. By trigonometry: Law of Sines F2 R 30 = = sinα sin 38° sin β α = 90° − 28° = 62 ° , β = 180° − 62° − 38° = 80° Then: F2 R 30 lb = = sin 62° sin 38° sin80° or (a) F 2 = 26.9 lb ! (b) R = 18.75 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 9. Using the Law of Sines F1 R 20 lb = = sinα sin 38° sin β α = 90° − 10° = 80 ° , β = 180° − 80° − 38° = 62° Then: F1 R 20 lb = = sin80° sin 38° sin 62° or (a) F 1 = 22.3 lb ! (b) R = 13.95 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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