Sol Cap 02 - Edicion 8

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COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 34. From Problem 2.23: ( 320 N) ( 600 N) F OA =− i + j ( 360 N) ( 150 N) F OB = i + j OC = ( 600N) − ( 110N) F i j ( 640 N) ( 640 N) R =Σ F = i + j ( 640 N) ( 640 N) R = + = 905.097 N 2 2 tanα = 640 N 640 N α = 45.0° R = 905 N 45.0° ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.
COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 35. Cable BC Force: 100-lb Force: 156-lb Force: and Further: Thus: ( ) 84 F x =− 145 lb =− 105 lb 116 ( ) 80 F y = 145 lb = 100 lb 116 ( ) 3 F x =− 100 lb =− 60 lb 5 ( ) 4 F y =− 100 lb =− 80 lb 5 ( ) 12 F x = 156 lb = 144 lb 13 ( ) 5 F y =− 156 lb =− 60 lb 13 R =Σ F =− 21 lb, R =Σ F =− 40 lb x x y y ( ) ( ) 2 2 R = − 21 lb + − 40 lb = 45.177 lb tanα = 40 21 −1 40 α = tan = 62.3° 21 R = 45.2 lb 62.3° ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.
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Sol Cap 02 - Edicion 8

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