Sol Cap 02 - Edicion 8

COSMOS: Complete Online Solutions Manual Organization System
Chapter 2, Solution 135.
(a) F = Fsin 30° sin 50° = 220.6 N (Given)
x
F
220.6 N
= = 575.95 N
sin30 ° sin50°
F = 576 N !
(b)
Fx
220.6
cosθ x = = = 0.38302
F 575.95
θ = 67.5°!
x
Fy
= Fcos30° = 498.79 N
Fy
498.79
cosθ y = = = 0.86605
F 575.95
θ = 30.0°!
y
Fz
=− Fsin 30° cos50°
=− ( 575.95 N)
sin 30° cos50°
=− 185.107 N
Fz
−185.107
cosθ
z = = = − 0.32139
F 575.95
θ = 108.7°!
z
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell
© 2007 The McGraw-Hill Companies.