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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 66. Free-Body Diagram: B (a) Have: T + F + T = 0 where magnitude and direction of of F AB is known. BD AB BC T BD are known, and the direction Then, in a force triangle: By observation, T BC is minimum when α = 90.0°⊳ (b) Have T = ( 310 N) sin ( 180° − 70° − 30° ) BC = 305.29 N TBC = 305 N ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 67. Free-Body Diagram At C: Since T AB = T = 140 lb, Force triangle is isosceles: BC With 2β + 75° = 180° β = 52.5° Then α = 90° − 52.5° − 30° α = 7.50° P ( 140 lb) cos52.5 2 = ° P = 170.453 lb P = 170.5 lb 7.50° ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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