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COSMOS: Complete Online <strong>Sol</strong>utions Manual Organization System<br />
Chapter 2, <strong>Sol</strong>ution 67.<br />
Free-Body Diagram At C:<br />
Since T<br />
AB<br />
= T = 140 lb, Force triangle is isosceles:<br />
BC<br />
With 2β + 75° = 180°<br />
β = 52.5°<br />
Then α = 90° − 52.5° − 30°<br />
α = 7.50°<br />
P<br />
( 140 lb)<br />
cos52.5<br />
2 = °<br />
P = 170.453 lb<br />
P = 170.5 lb 7.50° ⊳<br />
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,<br />
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell<br />
© 2007 The McGraw-Hill Companies.
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