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# Sol Cap 02 - Edicion 8

## COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 48. Free-Body Diagram At B: 12 17 Σ Fx = 0: − TBA + TBC = 0 13 293 or T = 1.07591 T BA BC Σ F y = T T T 0: BC BC BC or 5 2 TBA + TBC − 300 N = 0 13 293 ⎛ 5 ⎞ 293 = ⎜300 − TBA ⎟ ⎝ 13 ⎠ 2 = 2567.6 − 3.2918T BA ( T ) = 2567.6 − 3.2918 1.07591 T BC = 565.34 N BC Free-Body Diagram At C: 17 24 Σ F x = 0: − T 0 293 BC + T 25 CD = T CD 17 ⎛25 ⎞ = ( 565.34 N) ⎜ 293 24 ⎟ ⎝ ⎠ T CD = 584.86 N 2 7 Σ F y = 0: − T 0 293 BC + T 25 CD − W C = 2 7 W C =− + 293 25 ( 565.34 N) ( 584.86 N) or W = 97.7 N ! C Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 49. Free-Body Diagram: Σ F x = 0: −8 kips + 15 kips − T D cos 40° = 0 T D = 9.1378 kips Σ = 0: ( 9.1378 kips) sin 40°− = 0 F y T C T = 9.14 kips ! D T = 5.87 kips ! C Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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