Sol Cap 02 - Edicion 8

COSMOS: Complete Online Solutions Manual Organization System
Chapter 2, Solution 136.
(a) F Fcosθ
( )
Then:
z
= = 600 lb cos136.8°
z
=− 437.38 lb
F =− 437 lb !
2 2 2 2
= x + y + z
F F F F
z
2 2 2
2
F y
So: ( 600 lb) = ( 200 lb) + ( ) + ( − 437.38 lb)
2 2 2
Hence: F =− ( 600 lb) −( 200 lb) −( − 437.38 lb)
y
=− 358.75 lb
F =− 359 lb !
y
(b)
Fx
200
cosθ x = = = 0.33333
θ x = 70.5°!
F 600
Fy
−358.75
cosθ
y = = = − 0.59792 θ y = 126.7°!
F 600
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr.,
Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell
© 2007 The McGraw-Hill Companies.