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$(Microsoft PowerPoint - 03_Gruppi_Alcani [modalit\340 compatibilit ...$

x = k |k| > 4 x = 4 (4, 0) f f = 0 v = ρ 2 = x 2 + y 2 0 ≤ v ≤ 16 px(v) = 4(v − x) 3 − 27v 2 = 0, v v ≥ x 2 x x = v − 3v 2/3 / 3√ 4 v ≥ x 2 h(v) = v − 3v 2/3 / 3√ 4 x = h(v) 0 ≤ v ≤ 16 v ≥ h 2 (v) h ′ (v) = 1 − 2 1/3 /v 1/3 v = 2 h 0 < v < 2 2 < v < 16 x = h(v) 0 ≤ v ≤ 16 v ≥ x 2 − √ v ≤ x ≤ √ v h(v) = 0 v = 0 v = 27/4 0 < 2 < 27/4 < 16 h ]0, 27/4[ ]27/4, 16[ v h(v) h(16) = 4 − √ 16 ≤ 4 ≤ √ 16 x f(x, y) = 0 4 f(4, y) = 0 y = v − h 2 (v) v = 16 y = 0 x = h(v) f(x, y) h v = 2 h(2) = −1 − √ 2 < −1 − √ v v > 2 h(v) 2 < v < 16 − √ v ≤ h(v) = x (x, y) ∈ Γ x ≥ −1 −1 x Γ f(−1, y) = 0 5 − 6y 2 − 3y 4 + 4y 6 = 0 t = y 2 5 − 6t − 3t 2 + 4t 3 = 0 5 ±1, ±5 1 5 − 6t − 3t 2 + 4t 3 x − 1 4t 2 + t − 5 1 −5/4 f(−1, y) = 0 t = y 2 = 1 y = ±1 ∂xf(1, ±1) = 0 x y h(v) − √ v 2 < v < 16 2 4 2 < v < 16 h(v) 0 < x < 4 v h(v) = x x0 ≥ 0 f(x0, y) = 0 y y = ± 1 − h 2 (v) h 2 [0, 2] [2, 16] −1 < x < 0 v y f(x, y) = 0 y 2 Γ y 2 = v − h 2 (v) 1 − 2h(v)h ′ (v) = 5 3√ 2v 2/3 −2v−3·2 2/3 3√ v+1 y 2 x = −1/2 0 v = 1/4 1 − 2h(v)h ′ (v) v0 = 1/4 p(v) = 5 3√ 2v 2/3 − 2v − 3 · 2 2/3 3√ v + 1 p(1/4) = 0 v = 2t 3 p(t) = −4t 3 + 10t 2 − 6t + 1 1/4 = 2t 3 t = 1/2 p(t) t − 1/2
−2 + 8t − 4t 2 t = 1/2(2 ± √ 2) v1 = 1/4(2 − √ 2) 3 v2 = 1/4(2 + √ 2) 3 x0 = h(v0) = −1/2 x1 = h(v1) = 1/2 − 1/ √ 2 x2 = h(v2) = 1/2 + 1/ √ 2 x2 > 0 y > 0 f(x2, ±y) = 0 y + 2 = v2 − h 2 (v2) = 17/4 + 3 √ 2 y − 2 = −y+ 2 y2 Γ v1 y + 1 = v − h 2 (v) = Γ Q := [−1, 4] × [− 17/4 + 3 √ 2, 17/4 + 3 √ 2]. 17/4 − 3 √ 2 y − 1 = −y+ 1 0 < x < 4 (0, 3 √ 3/2) 1/2 + 1/ √ 2 17/4 + 3 √ 2 (4, 0) (4, 0) −1/2 ≤ x ≤ 0 (−1/2, 0) (0, 0) x 1/2 − 1/ √ 2 17/4 − 3 √ 2 −1 < x < −1/2 (−1, 1) (−1/2, 0) −1/2 < x < 0 −x + √ 3y = 9/2 x + √ 3y = −9/2 Γ (0, 3 √ 3/2) (0, −3 √ 3/2) x = −1 Γ (−1, ±1) Γ x = −1/2 (−1/2, 0) Γ x = 1/2 − 1/ √ 2 Γ −1/2 < x < 0 Γ (1/2 − 1/ √ 2, ± 17/4 − 3 √ 2) x = 0 Γ (0, ±3 √ 3/2) x = 1/2 + 1/ √ 2 Γ 0 < x < 4 Γ (1/2 + 1/ √ 2, ± 17/4 + 3 √ 2) Γ Γ 17/4 + 3 √ 2 x = 4 Γ (4, 0) Γ y = 17/4 + 3 √ 2 Γ (1/2 + 1/ √ 2, 17/4 + 3 √ 2) Γ y = 3 √ 3/2 Γ y = −1 Γ (−1, 1) Γ
Page 3 and 4:
R R n
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2 × 2 SO(
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R a
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R F G R F G ¯ F ⊇ G
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R n x, y ∈ Rn x = (x1, ...
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(X, τ) D ⊆ X X
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f : D → R D ⊆ Rn γ : [
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A =]0, +∞[×]0, +∞[ f : A →
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lim (x,y)→(0,0) (x,y)=(0,0) |xy|
Page 26 and 27:
E E E f −1 ([1, +∞[)
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s ↦→ 1 − e −s s ≥ 0 1
Page 30 and 31:
Fn : [0, +∞[→ R Fn(ρ) = 2n ρ
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I =]a, b[ R {fn}n∈N fn : I
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K [0, +∞[ R > 0 B(0, R) ⊇
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an = 0 n = 2k an = 4/(πn2 ) n
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5 1 18 = + 2 4 π2 ∞ n=0 ∞ n=0
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g(x) := x(π−x) x ∈ [0, π]
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X Y T : X → Y T ℓ >
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X K E X a, b ∈ R f : E × [a
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|f(x, y)| ≤ log(1 + 3y
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(x, y) ∈ R 2 xy =
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X, Y D ⊆ X f : D → Y u ∈
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H A 2 × 2 λ 2
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(2kπ, π/2+2hπ) (π+2kπ, 3π/2+2
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∂xf(x, y, z) = −2 cos x sin x =
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(0, 0) f : R 2 → R f(x, y) =
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α ∈ R (0, 0) f(x, y) = 2
Page 67: Cα > 0 α /∈ [−1/2, −1/4]
Page 70 and 71: x = cos θ y = sin θ θ ∈ [−π
Page 72 and 73: γ(t) = (t, 1/t) t → ±∞ L(x
Page 74 and 75: ⎧ ⎪⎨ 1 + λ(2x − 2) = 0, 1
Page 76 and 77: f(x, y) = x 2 + y 2 V = {(x, y)
Page 78 and 79: ⎧⎪ 2x + λ(2x + y) + 2µx = 0
Page 81 and 82: R 2 D ⊆ R 2 f : D → R (x0,
Page 83 and 84: x = 1 y = −1 z = 2 y z
Page 85: ⎛ 1 ⎜ 3 F (m1, m2, p1, p2) =
Page 88 and 89: k = 3√ 4 ξ ζ
Page 90 and 91: x = ρ cos θ y = ρ sin θ ρ 2 (
Page 92 and 93: f(x, y, z) = ez+x2 f + αx + y
Page 94 and 95: ϕ(1) = 0 ϕ ′ (1) = − ∂xf(1
Page 96 and 97: y 3 − xy 2 + x 2 y = x − x 3
Page 98 and 99: X = {(ρ, θ) ∈ R 2 : ρ > 0, 0 <
Page 100 and 101: arcsin sin θ = θ θ ∈] − π
Page 102 and 103: I R r : I → Rd γ µ : r
Page 104 and 105: γ lunghezza(γ) = |r ′ (θ)|
Page 106 and 107: p = 2 |(x, y)| −p dx dy = R 2 \B
Page 108 and 109: ρ 3 cos θ = aρ 2 (cos 2 θ − s
Page 111 and 112: Γ := {(x, y) ∈ R 2 : (x 2 + y 2
Page 113 and 114: x Γ Q2 Q3 x Γ \
Page 115 and 116: (x 2 + y 2 )(y 2 + x(x + 1)) = 4xy
Page 117: 4 ±1, ±2, ±4 ±1, ±2 4
Page 121 and 122: a ∈ R R 2 (x 2 + y 2 ) 3 = 4
Page 123: (x 2 + y 2 ) 3 = 4x 2 y 2
Page 127 and 128: a > 0 x = at at2 , y = . 1
Page 129: cos(π − α) = − cos(α) π/4
Page 132 and 133: I := F · ˆn dσ ˆn Σ =
Page 134 and 135: S ψ(x, y) = (ψ1, ψ2, ψ3) = (
Page 136 and 137: C = {(x, y, z) : (x, y) ∈ D, λ <
Page 138 and 139: ˆn = ∇G = ((∇G)1, (∇G)2, (
Page 140 and 141: 2π 0 cos θ sin θ dθ = 1 2 2π
Page 142 and 143: L − F · ˆn dσ = − L− √
Page 145 and 146: K ⊆ R n χK : R n → {0, 1}
Page 147 and 148: f [1, +∞[ [0, 1] [0
Page 149 and 150: f α k = 1 x α + k α , sα n = n
Page 151 and 152: D R X n 1 1 X C ℓ
Page 153 and 154: γ2(1/2) = (1/8, 3/4) γ2(1) = (0,
Page 155 and 156: C = −B ∂yu(x, y) = C/x 1 + y2 y
Page 157 and 158: dy N(x, y) = − dx M(x, y) N M
Page 159 and 160: 2xy dx + (x 2 + 1) dy = 0 (x 2 + y
Page 161 and 162: x − c = arcsin(2y − 1) 0 < y
Page 163: h(x, y) = 1/(|x| √ x2 − 1)
Page 166 and 167: ˙x = e t−x /x x(α) = 1 α ∈ R
Page 168 and 169:
˙x = x 2 /(1 − tx) x(0) = α α
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y ′′′ − 6y ′′ + 11y ′
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c ′ 1 (x) cos x + c′ 2 (x) sin
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y ′ + y 1 x = tan x sin x y ′
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λ 2 − 4λ − 5 = 0, A
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F (x, y, ˙y) = 0, F : A → R A
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F (x, y, p) = 0 c = 0 dy = p dx
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y = xy ′ + f(y ′ ) F (x, y, p
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y → 0 −∞
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x > 0 x y = ± 1 + x x < 0
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[0, π] utt + 2ut − uxx = 0,
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e |uk(x, t)| = C −t sin( 4k(1
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∞ n=1 bne −x sin nx = x(
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T ˙ Tn(t) = −5n 2 Tn(t) Tn(
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⎧ −utt + 3uxx = 0 ]0, π[×]0,
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∆ = 0 λ = −1 µ1 = µ2 = −
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x = cos θ y = sin θ F F (co
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I := arctan y dx − xy dy γ γ
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f(ρ) f ′ (ρ) = 4ρ3 + 36ρ 8
Page 210 and 211:
Jac ϕ(θ, y) = ⎛ ⎜ ⎝ − y
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z = (x, y) ˙z = Az + B(t)
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Q0 Q2 Q1 Q1
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˙x = t − x 2 x(0) = a a ∈ R
Page 219 and 220:
2π xt sin t F (x) = e dt x ∈ R
Page 221 and 222:
xz 3 dx dy dz, T T y
Page 223 and 224:
α > 0 lim (x,y)→(0,0) (x,y)=(0,0
Page 225 and 226:
F (0, 1) = 0 ∂yF (x, y) = 3y 2
Page 227 and 228:
(u + v) D 2 + (u − v) 2 1 + 2(u2
Page 229 and 230:
α = = 2 3 π. 2π 0
Page 231 and 232:
F D z = 0 (0,
Page 233 and 234:
y ′ = 2xy − x y(0) = 3/2
Page 235 and 236:
Γ f(x, y) = 0 f : R 2 → R
Page 237 and 238:
∇f(x0, y0) = (0, 0) (x0, y0)
Page 239 and 240:
ϕ : I ×J → R 3 I, J R
Page 241 and 242:
ψ(a, t) = ψ(b, t) t ∈]c, d[
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[
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Y K Ω R × Ω I R f :
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1 ω(x, y) = M(x, y) dx + N(x, y)
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M(x, y) dx + N(x, y) dy = 0 1 M, N
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x, y z dy dz
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f(x) = N(x) Ak1 = + D(x) x − xk
Page 256 and 257:
Φ y ′ = A(t) y ′ = A(t)
Page 258 and 259:
det P = 4 √ 7 = 0 P −1 AP
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y ′′ (t) + py ′ (t) + qy(t) =
Page 262 and 263:
y(0) = c1 + d1 = 1 ˙y(t) = (−c1
Page 264 and 265:
a ′ x + b ′ y + c ′ = 0
Page 266 and 267:
η2 g g(η) > 0 y0 < η <
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2 × 2 F ∈ R[x] n
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2 × 2 t ↦→ x(
Page 274 and 275:
∆ < 0 α = −d 2c ω = √ |
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a = 0 b = 0 c = 0 ⎧ ⎪⎨ b
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SO(3) U(3) := {O ∈
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SO(3) Aξ = ω × ξ ξ
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x 2 + y 2 = 1 x 2 − y 2 = 1
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1 arcsin(x) + x − x2 dx = √ 1
Page 288 and 289:
z 1 + cos z cos = ± 2 2 z 1
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