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cos(3θ) = cos θ(1 − 4 sin 2 θ) = cos θ(cos 2 θ − 3 sin 2 θ)<br />

Γ Γ <br />

<br />

2π<br />

3<br />

Γ P1 = (−1, 0) P2 = (1/2, √ 3/2) <br />

P3 = (1/2, − √ 3/2) <br />

Γ P0 y = ϕ1(x) ϕ1(−1) = 0<br />

ϕ ′ 1 (0)<br />

√ Γ P1 y = ϕ2(x) ϕ2(1/2) =<br />

3/2 ϕ ′<br />

2 (1/2)<br />

Γ P2 y = ϕ3(x) ϕ3(1/2) =<br />

− √ 3/2 ϕ ′ 3 (1/2)<br />

h(x, y) = x2 + y2 Γ Γ<br />

<br />

(3, 0) Γ<br />

<br />

F (x, y) = (x 2 + y 2 + 12x + 9) 2 − 4(2x + 3) 3 .<br />

F (x, y) =<br />

F (x, −y)<br />

cos 2 θ + sin 2 θ = 1 <br />

<br />

cos 3θ = cos(θ + 2θ) = cos θ cos 2θ − 2 sin 2 θ cos θ<br />

= cos θ(1 − 2 sin 2 θ) − 2 sin 2 θ cos θ = cos θ(1 − 4 sin 2 θ)<br />

F (ρ cos θ, ρ sin θ) = ρ 4 (sin 4 (θ) + cos 4 (θ) + 2 sin 2 (θ) cos 2 (θ))+<br />

+ ρ 3 (−8 cos 3 (θ) + 24 sin 2 (θ) cos(θ)) + 18ρ 2 − 27<br />

= ρ 4 (sin 2 (θ) + cos 2 (θ)) 2 − 8ρ 3 cos θ(cos 2 (θ) − 3 sin 2 (θ)) + 18ρ 2 − 27<br />

= ρ 4 − 8ρ 3 cos(3θ) + 18ρ 2 − 27<br />

θ 2π/3 <br />

2π/3 (0, 0) /∈ Γ <br />

f(ρ) := ρ4 + 18ρ 2 − 27<br />

8ρ 3<br />

= cos(3θ)<br />

Γ <br />

Γ (ρn, θn) ρn → +∞ <br />

lim sup<br />

+∞<br />

n→∞<br />

<br />

2π/3 <br />

∂yF (0, −1) = 0 ∂xF (0, −1) = 0<br />

(0, −1) x = −1 <br />

α = ±2π/3 <br />

<br />

− 1<br />

x ±<br />

2<br />

√<br />

3<br />

y = −1<br />

2<br />

√ 3 P3 − √ 3 P2

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