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R R n
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2 × 2 SO(
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R a
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R F G R F G ¯ F ⊇ G
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R n x, y ∈ Rn x = (x1, ...
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(X, τ) D ⊆ X X
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f : D → R D ⊆ Rn γ : [
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A =]0, +∞[×]0, +∞[ f : A →
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lim (x,y)→(0,0) (x,y)=(0,0) |xy|
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E E E f −1 ([1, +∞[)
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s ↦→ 1 − e −s s ≥ 0 1
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Fn : [0, +∞[→ R Fn(ρ) = 2n ρ
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I =]a, b[ R {fn}n∈N fn : I
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K [0, +∞[ R > 0 B(0, R) ⊇
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an = 0 n = 2k an = 4/(πn2 ) n
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5 1 18 = + 2 4 π2 ∞ n=0 ∞ n=0
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g(x) := x(π−x) x ∈ [0, π]
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X Y T : X → Y T ℓ >
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X K E X a, b ∈ R f : E × [a
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|f(x, y)| ≤ log(1 + 3y
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(x, y) ∈ R 2 xy =
- Page 53 and 54:
X, Y D ⊆ X f : D → Y u ∈
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H A 2 × 2 λ 2
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(2kπ, π/2+2hπ) (π+2kπ, 3π/2+2
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∂xf(x, y, z) = −2 cos x sin x =
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(0, 0) f : R 2 → R f(x, y) =
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α ∈ R (0, 0) f(x, y) = 2
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Cα > 0 α /∈ [−1/2, −1/4]
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x = cos θ y = sin θ θ ∈ [−π
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γ(t) = (t, 1/t) t → ±∞ L(x
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⎧ ⎪⎨ 1 + λ(2x − 2) = 0, 1
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f(x, y) = x 2 + y 2 V = {(x, y)
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⎧⎪ 2x + λ(2x + y) + 2µx = 0
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R 2 D ⊆ R 2 f : D → R (x0,
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x = 1 y = −1 z = 2 y z
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⎛ 1 ⎜ 3 F (m1, m2, p1, p2) =
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k = 3√ 4 ξ ζ
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x = ρ cos θ y = ρ sin θ ρ 2 (
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f(x, y, z) = ez+x2 f + αx + y
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ϕ(1) = 0 ϕ ′ (1) = − ∂xf(1
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y 3 − xy 2 + x 2 y = x − x 3
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X = {(ρ, θ) ∈ R 2 : ρ > 0, 0 <
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arcsin sin θ = θ θ ∈] − π
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I R r : I → Rd γ µ : r
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γ lunghezza(γ) = |r ′ (θ)|
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p = 2 |(x, y)| −p dx dy = R 2 \B
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ρ 3 cos θ = aρ 2 (cos 2 θ − s
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Γ := {(x, y) ∈ R 2 : (x 2 + y 2
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x Γ Q2 Q3 x Γ \
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(x 2 + y 2 )(y 2 + x(x + 1)) = 4xy
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4 ±1, ±2, ±4 ±1, ±2 4
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−2 + 8t − 4t 2 t = 1/2(2
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a ∈ R R 2 (x 2 + y 2 ) 3 = 4
- Page 123: (x 2 + y 2 ) 3 = 4x 2 y 2
- Page 127 and 128: a > 0 x = at at2 , y = . 1
- Page 129: cos(π − α) = − cos(α) π/4
- Page 132 and 133: I := F · ˆn dσ ˆn Σ =
- Page 134 and 135: S ψ(x, y) = (ψ1, ψ2, ψ3) = (
- Page 136 and 137: C = {(x, y, z) : (x, y) ∈ D, λ <
- Page 138 and 139: ˆn = ∇G = ((∇G)1, (∇G)2, (
- Page 140 and 141: 2π 0 cos θ sin θ dθ = 1 2 2π
- Page 142 and 143: L − F · ˆn dσ = − L− √
- Page 145 and 146: K ⊆ R n χK : R n → {0, 1}
- Page 147 and 148: f [1, +∞[ [0, 1] [0
- Page 149 and 150: f α k = 1 x α + k α , sα n = n
- Page 151 and 152: D R X n 1 1 X C ℓ
- Page 153 and 154: γ2(1/2) = (1/8, 3/4) γ2(1) = (0,
- Page 155 and 156: C = −B ∂yu(x, y) = C/x 1 + y2 y
- Page 157 and 158: dy N(x, y) = − dx M(x, y) N M
- Page 159 and 160: 2xy dx + (x 2 + 1) dy = 0 (x 2 + y
- Page 161 and 162: x − c = arcsin(2y − 1) 0 < y
- Page 163: h(x, y) = 1/(|x| √ x2 − 1)
- Page 166 and 167: ˙x = e t−x /x x(α) = 1 α ∈ R
- Page 168 and 169: ˙x = x 2 /(1 − tx) x(0) = α α
- Page 170 and 171: y ′′′ − 6y ′′ + 11y ′
- Page 172 and 173: c ′ 1 (x) cos x + c′ 2 (x) sin
- Page 176 and 177: Ω (0, 0) (x0, z0) V (
- Page 178 and 179: y = ˙x + 2x − 4t2 ˙y = 3x + 2y
- Page 180 and 181: ⎧ ⎪⎨ y = f(p, C), ∂pf(p, C
- Page 182 and 183: F (x, y, p) = 0 c = 0 dy = p dx
- Page 185 and 186: α ∈ R x ≥ 0 y ′ (x) =
- Page 187 and 188: ˙y = 1 − x 2 y 2 y(0) = α α
- Page 189: y ′ = y 4 − x2 y(1) = 0 (1 + |
- Page 192 and 193: µ 2 + 2µ + n 2 = 0 ∆ = 4(1
- Page 194 and 195: u(t, x) = T (t)X(x) ˙ T (t)X(x
- Page 197 and 198: [0, π] ut − 5uxx = 0, 0 ≤
- Page 199 and 200: λ ∈ R X(x) λ ∈ R 2
- Page 201 and 202: a0 = 1 π an = 2 π π 0 π 0
- Page 203 and 204: f : R 2 → R D := {(x, y)
- Page 205 and 206: α < 2 N n=1 fn(x, y, α)
- Page 207 and 208: cos(3θ) = cos θ(1 − 4 sin 2 θ)
- Page 209 and 210: div F (x, y, z) = ∂xF1 + ∂yF2
- Page 211 and 212: 2π 0 cos θ sin θ dθ = 1 2 2π
- Page 213 and 214: a (−∞, 0] a
- Page 215 and 216: 0 < log 1 − a 1 + a < 2 |1 −
- Page 217: ω = n ∈ Z ω λ < 0 λ
- Page 220 and 221: f(x, y, z) = x 2 +y 2 +z 2 x+y+z
- Page 222 and 223: 1 Jac ϕ(θ) 1 ds =
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f f(x, y) > 0 f |(x, y)| →
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1 A = √ 1−y2 √ 2/2 − √ 1
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Jac ϕ(θ, y) = ⎛ ⎜ ⎝ − y
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ω2 = det 2 B1 + det 2 B2 + det 2 B
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ω1(x, y) = yx y−1 dx + x y log x
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λω = ( 1 x2 − y) dx + (y − x)
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f Γ f(x,
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˜ F A A A (
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dσ = det 2 B1 + det 2 B2 + det 2 B
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p, q ∈ N q 2π 0 cos p θ sin
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t ∈ I LK > 0 f(t, y1) −
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ϕ ∈ C1 (I, Y ) ϕ ′ (t) ≤
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C R 2 x = ξ, y = ξη 1 N(
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F Fc := {(x, y) ∈ A : F (x, y
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K Y K = R C Y = R n
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a, b ∈ C 0 (I, K) I R A(t) ∈
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y1 y2 c ′ 1y ′ 1 + c
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uj n y(t) = e (t
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(t) = a(t)e αt α ∈ R a(t)
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y ′ = f(x, y) A
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t > 0 t = es y(es ) = u(s)
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Ω ⊆ R n F : Ω → R n C 1
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2 × 2 b = 0 ˙x y
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a∂ttu(t, x) + b∂tu(t, x) + c∂
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λ λ λn = − d2 + 4c 2 n 2
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u(t, x) = 1 π f(s) ds π 0 e −
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SO(3) λ1 = 1 e 2α = 1 α = 0
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R 2 γ 1 x 2 +y 2 = 1
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d −1 1 sinh x = √ dx x2 + 1 d
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z ∈ C e z ∞ z = Re(z)(cos(Im(z)
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z 1 + cos z cos = ± 2 2 z 1