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√<br />

2<br />

(0, 1/2) f f(0, 1/2) =<br />

2 e−1/4 D x = cos t y = sin t + 1 t ∈ [0, 2π[ <br />

<br />

h(t) := f(cos t, sin t + 1) = e −2(sin(t)+1) sin(t) + 1.<br />

h ′ (t) = − e−2(sin(t)+1) (4 sin(t) + 3) cos(t)<br />

2 .<br />

sin(t) + 1<br />

cos t = 0 t = π/2, 3π/2 sin t = −3/4 <br />

t (0, 0) (0, 2) (± √ 7/4, 1/4) f(0, 0) = 0 f(0, 2) = √ 2e−4 f(± √ 7/4, 1/4) =<br />

e−1/2 √<br />

2<br />

/2 f(0, 1/2) =<br />

2 e−1/4 (0, 0) <br />

(0, 1/2)

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