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(2kπ, π/2+2hπ) (π+2kπ, 3π/2+2hπ) h, k ∈ Z<br />

1<br />

(2kπ, 3π/2+2hπ) (π +2kπ, π/2+2hπ) h, k ∈ Z<br />

−1<br />

(π/2 + kπ, hπ) h, k ∈ Z <br />

<br />

∂xf(x, y) = 4x 3 + 2xy = x(4x 2 + y), ∂yf(x, y) = x 2 + 2y.<br />

(0, 0) <br />

∂ 2 xxf(x, y) = 12x 2 + 2y ∂ 2 yyf(x, y) = 2 ∂ 2 xyf(x, y) = 2x <br />

<br />

D 2 f(0, 0) =:<br />

0 0<br />

0 2<br />

<br />

.<br />

(0, 0) <br />

f(x, y) = g(x 2 , y) g(v, w) = v 2 + vw + w 2 + 3 <br />

v 2 + vw + w 2 v > 0 v = x 2 > 0 x = 0 v > 0 <br />

v 2 + vw + w 2 = 0 w <br />

v 2 − 4v 2 < 0 v 2 + vw + w 2 v > 0 <br />

w → ±∞ v > 0 <br />

f(x, y) = g(x 2 , y) > 3 = f(0, 0) x = 0 (0, 0)<br />

<br />

f(x, y) = x 4 + y 4 − 2(x 2 + y 4 ) + 4xy <br />

∂xf(x, y) = 4x 3 − 4x + 4y, ∂yf(x, y) = −4y 3 + 4x.<br />

x = y 3 4y 9 − 4y 3 + 4y = 0 x = y 3 <br />

y(y 8 −y 2 +1) = 0 (0, 0) <br />

y 8 −y 2 +1 = 0 y = 0 0 < |y| ≤ 1 1−y 2 ≥ 0 y 8 −y 2 +1 ≥ y 8 > 0<br />

|y| > 1 y 8 > y 2 y 8 − y 2 + 1 > 1 > 0 <br />

∂ 2 xxf(x, y) = 12x 2 − 4 ∂ 2 yyf(x, y) = −12y 2 ∂ 2 xyf(x, y) = 4<br />

<br />

D 2 f(0, 0) =:<br />

−4 4<br />

4 0<br />

<br />

,<br />

λ 2 + 4λ − 16 = 0 λ = −2 ± 2 √ 5

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