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1 arcsin(x) + x − x2 dx = √ 1 − x2 + c 2 x arcsinh(x) + x 2 + 1 dx = √ x2 + 1 2 x −arccosh(x) + x 2 − 1 dx = √ x2 − 1 2 + c = ln(x + √ x 2 + 1) + x √ x 2 + 1 2 + c + c = − ln(x + √ x 2 − 1) + x √ x 2 − 1 2 dx = arctan(x) + c 1 + x2 dx 1 = arctanh(x) + c = 1 − x2 2 ln 1 + x + c 1 − x + c
z ∈ C e z ∞ z = Re(z)(cos(Im(z)) + i sin(Im(z))) = n n! cos z = eiz + e −iz 2 sin z = eiz − e −iz 2i tan z = cot z = n=0 = cosh iz cosh z = ez + e −z = cos iz 2 = −i sinh iz sinh z = ez − e −z = −i sin iz 2 sin z cos z = eiz − e −iz eiz + e−iz = e2iz − 1 e2iz sinh z = −i tanh(iz) tanh z = + 1 cosh z = ez − e −z ez + e−z = e2z − 1 e2z = −i tan(iz) + 1 cos z sin z = eiz + e −iz eiz − e−iz = e2iz + 1 e2iz cosh z = i coth(iz) coth z = − 1 sinh z = ez + e −z ez − e−z = e2z + 1 e2z = i cot(iz) − 1 cos 2 z + sin 2 z = 1 cosh 2 z − sinh 2 z = 1 cos(z1 ± z2) = cos z1 cos z2 ∓ sin z1 sin z2 sin(z1 ± z2) = sin z1 cos z2 ± cos z1 sin z2 tan(z1 ± z2) = cot(z1 ± z2) = tan z1 ± tan z2 1 ∓ tan z1 tan z2 cot z1 cot z2 ∓ 1 cot z2 ± cot z1 cosh(z1 ± z2) = cosh z1 cosh z2 ± sinh z1 sinh z2 sinh(z1 ± z2) = sinh z1 cosh z2 ± cosh z1 sinh z2 tanh(z1 ± z2) = coth(z1 ± z2) = tanh z1 ± tanh z2 1 ± tanh z1 tanh z2 coth z1 coth z2 ± 1 coth z2 ± coth z1 cos(2z) = cos 2 z − sin 2 z = 2 cos 2 z − 1 = 1 − 2 sin 2 z cosh(2z) = cosh 2 z + sinh 2 z = 2 cosh 2 z − 1 = 1 + 2 sinh 2 z sin(2z) = 2 sin z cos z sinh(2z) = 2 sinh z cosh z tan(2z) = 2 tan z 1 − tan2 (z) cot(2z) = cot2 (z) − 1 2 cot z tanh(2z) = 2 tanh z 1 + tanh 2 (z) coth(2z) = coth2 (z) + 1 2 coth z
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R R n
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2 × 2 SO(
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R a
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R F G R F G ¯ F ⊇ G
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R n x, y ∈ Rn x = (x1, ...
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(X, τ) D ⊆ X X
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f : D → R D ⊆ Rn γ : [
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A =]0, +∞[×]0, +∞[ f : A →
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lim (x,y)→(0,0) (x,y)=(0,0) |xy|
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E E E f −1 ([1, +∞[)
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s ↦→ 1 − e −s s ≥ 0 1
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Fn : [0, +∞[→ R Fn(ρ) = 2n ρ
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I =]a, b[ R {fn}n∈N fn : I
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K [0, +∞[ R > 0 B(0, R) ⊇
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an = 0 n = 2k an = 4/(πn2 ) n
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5 1 18 = + 2 4 π2 ∞ n=0 ∞ n=0
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g(x) := x(π−x) x ∈ [0, π]
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X Y T : X → Y T ℓ >
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X K E X a, b ∈ R f : E × [a
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|f(x, y)| ≤ log(1 + 3y
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(x, y) ∈ R 2 xy =
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X, Y D ⊆ X f : D → Y u ∈
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H A 2 × 2 λ 2
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(2kπ, π/2+2hπ) (π+2kπ, 3π/2+2
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∂xf(x, y, z) = −2 cos x sin x =
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(0, 0) f : R 2 → R f(x, y) =
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α ∈ R (0, 0) f(x, y) = 2
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Cα > 0 α /∈ [−1/2, −1/4]
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x = cos θ y = sin θ θ ∈ [−π
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γ(t) = (t, 1/t) t → ±∞ L(x
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⎧ ⎪⎨ 1 + λ(2x − 2) = 0, 1
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f(x, y) = x 2 + y 2 V = {(x, y)
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⎧⎪ 2x + λ(2x + y) + 2µx = 0
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R 2 D ⊆ R 2 f : D → R (x0,
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x = 1 y = −1 z = 2 y z
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⎛ 1 ⎜ 3 F (m1, m2, p1, p2) =
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k = 3√ 4 ξ ζ
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x = ρ cos θ y = ρ sin θ ρ 2 (
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f(x, y, z) = ez+x2 f + αx + y
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ϕ(1) = 0 ϕ ′ (1) = − ∂xf(1
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y 3 − xy 2 + x 2 y = x − x 3
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X = {(ρ, θ) ∈ R 2 : ρ > 0, 0 <
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arcsin sin θ = θ θ ∈] − π
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I R r : I → Rd γ µ : r
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γ lunghezza(γ) = |r ′ (θ)|
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p = 2 |(x, y)| −p dx dy = R 2 \B
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ρ 3 cos θ = aρ 2 (cos 2 θ − s
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Γ := {(x, y) ∈ R 2 : (x 2 + y 2
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x Γ Q2 Q3 x Γ \
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(x 2 + y 2 )(y 2 + x(x + 1)) = 4xy
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4 ±1, ±2, ±4 ±1, ±2 4
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−2 + 8t − 4t 2 t = 1/2(2
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a ∈ R R 2 (x 2 + y 2 ) 3 = 4
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(x 2 + y 2 ) 3 = 4x 2 y 2
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a > 0 x = at at2 , y = . 1
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cos(π − α) = − cos(α) π/4
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I := F · ˆn dσ ˆn Σ =
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S ψ(x, y) = (ψ1, ψ2, ψ3) = (
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C = {(x, y, z) : (x, y) ∈ D, λ <
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ˆn = ∇G = ((∇G)1, (∇G)2, (
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2π 0 cos θ sin θ dθ = 1 2 2π
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L − F · ˆn dσ = − L− √
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K ⊆ R n χK : R n → {0, 1}
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f [1, +∞[ [0, 1] [0
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f α k = 1 x α + k α , sα n = n
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D R X n 1 1 X C ℓ
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γ2(1/2) = (1/8, 3/4) γ2(1) = (0,
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C = −B ∂yu(x, y) = C/x 1 + y2 y
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dy N(x, y) = − dx M(x, y) N M
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2xy dx + (x 2 + 1) dy = 0 (x 2 + y
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x − c = arcsin(2y − 1) 0 < y
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h(x, y) = 1/(|x| √ x2 − 1)
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˙x = e t−x /x x(α) = 1 α ∈ R
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˙x = x 2 /(1 − tx) x(0) = α α
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y ′′′ − 6y ′′ + 11y ′
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c ′ 1 (x) cos x + c′ 2 (x) sin
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y ′ + y 1 x = tan x sin x y ′
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λ 2 − 4λ − 5 = 0, A
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F (x, y, ˙y) = 0, F : A → R A
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F (x, y, p) = 0 c = 0 dy = p dx
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y = xy ′ + f(y ′ ) F (x, y, p
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y → 0 −∞
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x > 0 x y = ± 1 + x x < 0
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[0, π] utt + 2ut − uxx = 0,
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e |uk(x, t)| = C −t sin( 4k(1
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∞ n=1 bne −x sin nx = x(
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T ˙ Tn(t) = −5n 2 Tn(t) Tn(
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⎧ −utt + 3uxx = 0 ]0, π[×]0,
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∆ = 0 λ = −1 µ1 = µ2 = −
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x = cos θ y = sin θ F F (co
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I := arctan y dx − xy dy γ γ
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f(ρ) f ′ (ρ) = 4ρ3 + 36ρ 8
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Jac ϕ(θ, y) = ⎛ ⎜ ⎝ − y
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z = (x, y) ˙z = Az + B(t)
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Q0 Q2 Q1 Q1
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˙x = t − x 2 x(0) = a a ∈ R
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2π xt sin t F (x) = e dt x ∈ R
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xz 3 dx dy dz, T T y
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α > 0 lim (x,y)→(0,0) (x,y)=(0,0
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F (0, 1) = 0 ∂yF (x, y) = 3y 2
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(u + v) D 2 + (u − v) 2 1 + 2(u2
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α = = 2 3 π. 2π 0
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F D z = 0 (0,
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y ′ = 2xy − x y(0) = 3/2
Page 235 and 236: Γ f(x, y) = 0 f : R 2 → R
Page 237 and 238: ∇f(x0, y0) = (0, 0) (x0, y0)
Page 239 and 240: ϕ : I ×J → R 3 I, J R
Page 241 and 242: ψ(a, t) = ψ(b, t) t ∈]c, d[
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Page 245 and 246: Y K Ω R × Ω I R f :
Page 247 and 248: 1 ω(x, y) = M(x, y) dx + N(x, y)
Page 249 and 250: M(x, y) dx + N(x, y) dy = 0 1 M, N
Page 251: x, y z dy dz
Page 254 and 255: f(x) = N(x) Ak1 = + D(x) x − xk
Page 256 and 257: Φ y ′ = A(t) y ′ = A(t)
Page 258 and 259: det P = 4 √ 7 = 0 P −1 AP
Page 260 and 261: y ′′ (t) + py ′ (t) + qy(t) =
Page 262 and 263: y(0) = c1 + d1 = 1 ˙y(t) = (−c1
Page 264 and 265: a ′ x + b ′ y + c ′ = 0
Page 266 and 267: η2 g g(η) > 0 y0 < η <
Page 269 and 270: 2 × 2 F ∈ R[x] n
Page 271: 2 × 2 t ↦→ x(
Page 274 and 275: ∆ < 0 α = −d 2c ω = √ |
Page 276 and 277: a = 0 b = 0 c = 0 ⎧ ⎪⎨ b
Page 279 and 280: SO(3) U(3) := {O ∈
Page 281: SO(3) Aξ = ω × ξ ξ
Page 284 and 285: x 2 + y 2 = 1 x 2 − y 2 = 1
Page 288 and 289: z 1 + cos z cos = ± 2 2 z 1
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