reservoir geomecanics

96 Reservoir geomechanics
a. b.
1250
800
s 1 (MPa)
1000
750
s 3
= 85
s 3
= 105
s 3
= 65
s 3
= 45
s 3
(MPa)
500
s 3
= 25
s 3 = 25
s 3 = 45
s 3 = 65
250
Dunham dolomite
s 3 = 85
C0 = 450 MPa
s 3 = 105
m i = 0.65
s 3 = 125
Mean misfit = 56.0 MPa
s 3 = 145
0
0 200 400 600 800 1000 1200
s 2 (MPa)
s 1
= s 2
s 3
= 125
s 3
= 145
s 1 (MPa)
700
600
500
400
300
s 3
= 20
s 3
= 40
s 1
= s 2
s 3
= 60
s 3
= 80
200
s 3 (MPa)
Solenhofen limestone s 3 = 20
C0 = 375 MPa
s 3 = 40
100
m i = 0.55
s 3 = 60
Mean misfit = 37.1 MPa
s 3 = 80
0
0 100 200 300 400 500 600 700 800
s 2 (MPa)
c. d.
350
350
300
300
s 3
= 40
250
s 3
= 30
250
s 3
= 50
s 1 (MPa)
200
150
100
50
s 3
= 5
s 3
= 8
s 3
= 15
s 3
= 20
s 1
= s 2
Shirahama sandstone
C 0 = 95 MPa
m i = 0.8
Mean misfit = 9.6 MPa
s 3
(MPa)
s 3
= 5
s 3
= 8
s 3
= 15
s 3
= 20
s 3
= 30
s 3
= 40
0
0 50 100 150 200 250 300
s 2 (MPa)
s 1 (MPa)
200
150
100
s 3
= 25
s 1
= s 2
Yuubari shale
s 3 (MPa)
50
C 0 = 120 MPa
s 3 = 25
m i = 0.5
s 3 = 50
Mean misfit = 13.5 MPa
0
0 50 100 150 200 250 300
s 2 (MPa)
e.
2000
1800
1600
1400
s 3
= 150
s 1 (MPa)
1200
1000
s 3
= 100
800
s 3
= 60
s 1
= s 2
600
s
s 3
= 30
3 (MPa)
s 3 = 0
400
s
KTB amphibolite
3
= 0
C 0 = 300 MPa
s 3 = 30
s 3 = 60
200
m i = 1.2
s 3 = 100
Mean misfit = 77.9 MPa s 3 = 150
0
0 500
s 2 (MPa)
1000 1500
Figure 4.8. Best-fitting solution for all the rocks using the Mohr–Coulomb criterion. (a) Dunham
dolomite. (b) Solenhofen limestone. (c) Shirahama sandstone. (d) Yuubari shale. (e) KTB
amphibolite. After Colmenares and Zoback (2002). Reprinted with permission of Elsevier.