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FOUNDATIONS OF QUANTUM MECHANICS

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102 CHAPTER IV. THE COPENHAGEN INTERPRETATION<br />

and<br />

yielding<br />

(∆ ψss P ) 2 =<br />

∫<br />

R<br />

p 2 | ˜ψ ss (p)| 2 dp = 1<br />

π a<br />

∫<br />

R<br />

| sin(ap)| 2 dp = ∞, (IV. 46)<br />

∆ ψss Q ∆ ψss P = 1 3√<br />

3 a ∞. (IV. 47)<br />

This indeed satisfies the Kennard inequality (IV. 26), but in a little interesting manner.<br />

Although ∆ ψss P = ∞, the function | ˜ψ ss | 2 has in fact a very pronounced central peak, of a width<br />

of the order a −1 , in which 95% of the total probability is located. It is the inverse proportionality<br />

of the width of this central peak to the width of the slit, which, according to Heisenberg, illustrates<br />

the uncertainty principle; it is impossible to make the probability densities |ψ ss (q)| 2 and | ˜ψ ss (p)| 2<br />

arbitrarily small at the same time.<br />

But this conclusion can not be inferred from the Kennard inequality (IV. 26). If a goes to infinity,<br />

| ˜ψ ss (p)| 2 goes to the delta function δ (p). The standard deviation ∆ ψss P , however, remains<br />

divergent. In other words, 95% of a probability distribution can be concentrated on an arbitrarily<br />

small interval, whereas the standard deviation of the distribution remains arbitrarily large. 2 If nothing<br />

is given concerning the distributions |ψ ss (q)| 2 and | ˜ψ ss (p)| 2 but the Kennard inequality (IV. 26),<br />

these distributions could both be very narrow, and, consequently, Heisenberg’s conclusion can not be<br />

derived from the Kennard inequality, in contrast to what is usually claimed.<br />

Nevertheless, Heisenberg’s conclusion is correct for the given example of the single slit. This<br />

raises the question if his statement is valid in general. What we are in fact interested in is a measure<br />

for the width of a probability distribution representing the width of the unweighted distribution.<br />

The most natural definition of such a measure is the smallest interval a fraction α ∈ [0, 1] of<br />

the total probability can be in, where, roughly, α = 0.95 is taken. If ρ is a probability density, the<br />

definition is<br />

{<br />

∫ b<br />

}<br />

W α (ρ) := min [a, b] ⊂ R ∣ ρ(x) dx = α . (IV. 48)<br />

a<br />

For position and momentum in quantum mechanics we define<br />

{<br />

∫ b<br />

}<br />

W α (Q, ψ) := min [a, b] ⊂ R ∣ |ψ(q)| 2 dq = α , (IV. 49)<br />

{<br />

W α (P, ψ) := min [a, b] ⊂ R<br />

∣<br />

a<br />

∫ b<br />

a<br />

| ˜ψ(p)|<br />

}<br />

2 dp = α . (IV. 50)<br />

The product of these measures also satisfy an uncertainty relation, as was shown for the first time by<br />

H.J. Landau and H.O. Pollak (1961), nota bene in a journal for industrial engineers of the American<br />

Bell Telephone Company,<br />

W α (P, ψ) W α (Q, ψ) c α , (IV. 51)<br />

where α ∈ ( 1<br />

2 , 1] , and c α > 0 is a constant which only depends on α, not on ψ.<br />

2 Responsible for this phenomenon is the mathematical fact that the standard deviation assigns a quadratically increasing<br />

weight to the tails of a distribution. In a Gaussian distribution, e.g. the Gaussian wave packet (IV. 32), these tails go to zero<br />

rapidly enough because an exponential power goes to zero more rapidly than any polynomial goes to infinity, but for many<br />

wave functions occurring in physics the standard deviation diverges.

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