01.06.2014 Views

FOUNDATIONS OF QUANTUM MECHANICS

FOUNDATIONS OF QUANTUM MECHANICS

FOUNDATIONS OF QUANTUM MECHANICS

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

112 CHAPTER V. HIDDEN VARIABLES<br />

(iii) The range of A : Λ → R coincides with the spectrum of the self - adjoint operator A which,<br />

according to quantum mechanics, corresponds to quantity A.<br />

The expectation value of A when the physical system is in the state ρ W which, according<br />

to quantum mechanics, corresponds to the state operator W , equals the quantum mechanical<br />

expression for the expectation value<br />

⟨A⟩ ρW :=<br />

∫<br />

Λ<br />

A[λ] ρ W (λ) dλ = Tr AW.<br />

We will call this last requirement (iii) the reproduction criterion.<br />

Since all probabilities in quantum mechanics can be written as Tr PW , with P ∈ P(H), it follows<br />

that all probability distributions in quantum mechanics coincide with the corresponding probability<br />

distributions in the HVT.<br />

We can now ask whether it is possible to construct a HVT satisfying the above requirements. The<br />

answer is that it is indeed possible, even in a quite trivial way, by choosing Λ large enough. We<br />

illustrate this by means of a simple example.<br />

Suppose there are only three quantities A, B, C, with possible values {a 1 }, {b 1 , b 2 }, {c 1 , c 2 } and<br />

represented by functions A, B, C : Λ → R. The possible value combinations are<br />

(a 1 , b 1 , c 1 ), (a 1 , b 1 , c 2 ), (a 1 , b 2 , c 1 ), (a 1 , b 2 , c 2 ). (V. 4)<br />

We now construct a space Λ by identifying every value combination with a point of Λ. If we denote<br />

these points by λ 1 , λ 2 , λ 3 and λ 4 , then<br />

A[λ 1 ] = a 1 , B[λ 3 ] = b 2 , C [λ 4 ] = c 2 , etc. (V. 5)<br />

When there are more quantities, we extend Λ correspondingly.<br />

We have to introduce a probability measure<br />

µ : F (Λ) → [0, 1] with<br />

∑<br />

µ(λ j ) = 1 (V. 6)<br />

j<br />

such that (V. 1) is satisfied. In our case Λ is discrete and consists of four points only, as a result of<br />

which the integral (V. 1) becomes a sum. For example, to quantity B it must apply that<br />

Tr B W =<br />

4∑<br />

B[λ j ] µ W (λ j )<br />

j=1<br />

This is satisfied by<br />

= b 1<br />

(<br />

µW (λ 1 ) + µ W (λ 2 ) ) + b 2<br />

(<br />

µW (λ 3 ) + µ W (λ 4 ) ) . (V. 7)<br />

µ W (a i , b j , c k ) = Tr P ai W Tr P bj W Tr P ck W, (V. 8)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!