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FOUNDATIONS OF QUANTUM MECHANICS

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VII. 5. STOCHASTIC HIDDEN VARIABLES 157<br />

3. Source independence. We already discussed the possibility of violation of the Bell inequalities<br />

by a super-deterministic theory without source independence. It is a philosophical question whether<br />

we can somehow establish if we have free will or not, therefore, it is a possibility, but not an inevitability,<br />

leaving outcome and parameter independence.<br />

2. Parameter independence. Describing the pairs of particles in the singlet state |Ψ 0 ⟩, (III. 165),<br />

by a pure hidden - variables state, the probability distribution is a delta - distribution,<br />

ρ Ψ0 (λ) = δ λ0 (λ) := δ(λ − λ 0 ), (VII. 71)<br />

which leads to<br />

∫<br />

p ⃗a, ⃗ b,λ0<br />

(a, b, λ) ρ Ψ0 (λ) dλ = p ⃗a, ⃗ b,λ0<br />

(a, b). (VII. 72)<br />

Λ<br />

The probabilities for the outcomes of measurement are given by (III. 176),<br />

p ⃗a, ⃗ b,λ0<br />

(a = 1 ∧ b = 1) = 1 2 sin2 1 2 θ ⃗a, ⃗ b ,<br />

p ⃗a, ⃗ b,λ0<br />

(a = 1 ∧ b = −1) = 1 2 cos2 1 2 θ ⃗a, ⃗ . (VII. 73)<br />

b<br />

EXERCISE 33. Also calculate the other two joint probabilities, that is, for a = 1 ∧ b = 1<br />

and a = −1 ∧ b = 1.<br />

The marginal probabilities are, using (VII. 73),<br />

p ⃗a, ⃗ b<br />

(a | λ 0 ) = p ⃗a, ⃗ b,λ0<br />

(a = 1 ∧ b = 1) + p ⃗a, ⃗ b,λ0<br />

(a = 1 ∧ b = −1) = 1 2 ,<br />

p ⃗a, ⃗ b<br />

(b | λ 0 ) = p ⃗a, ⃗ b,λ0<br />

(a = 1 ∧ b = 1) + p ⃗a, ⃗ b,λ0<br />

(a = −1 ∧ b = 1) = 1 2<br />

, (VII. 74)<br />

which means that, both being equal to 1 2<br />

, they are not dependent of the settings of a remote measuring<br />

device. Consequently, even the quantum mechanical correlations in the singlet cannot be used for<br />

signaling, there is no actio in distans, leading to the following theorem.<br />

NO - SIGNALING THEOREM:<br />

Quantum mechanics satisfies parameter independence, i.e., if subsystems of a composite<br />

physical system no longer interact, the probability of finding certain outcomes of measurement<br />

for an arbitrary quantity of subsystem 1 is independent of which quantity of<br />

subsystem 2 is measured, and vice versa.<br />

EXERCISE 34. Prove that the EPRB experiment is an example of the no - signaling theorem.<br />

Optional: prove, in general, the no - signaling theorem using state operators. Whoever cannot<br />

solve this problem, is advised to consult Ghirardi, Rimini and Weber (1980).

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