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FOUNDATIONS OF QUANTUM MECHANICS

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Now consider an operator W of the form<br />

III. 4. COMPOSITE SYSTEMS 61<br />

W =<br />

∑N I<br />

∑N II<br />

i=1 j=1<br />

which is, in general, not factorizable.<br />

z ij U i ⊗ V j , (III. 93)<br />

EXERCISE 20. Prove that U i ⊗ V j is a 1 - dimensional projector in H.<br />

The operator W , (III. 93), is a state operator if<br />

z ij ∈ [0, 1] and<br />

∑N I<br />

∑N II<br />

i=1 j=1<br />

z ij = 1, (III. 94)<br />

furthermore, with (III. 69) and (III. 72) we have<br />

and<br />

Tr II W =<br />

Tr I W =<br />

∑N I<br />

∑N II<br />

i=1 j=1<br />

∑N I<br />

∑N II<br />

i=1 j=1<br />

z ij U i (III. 95)<br />

z ij V j . (III. 96)<br />

This system has an infinite number of solutions for the unknown z ij , unless one of the partial<br />

traces is pure, e.g. Tr II W = U 1 . In that case, according to (III. 95) it has to hold for i = 1<br />

that ∑ j z 1j = 1. But then (III. 35) requires that ∑ j z ij = 0 if i ≠ 1, which means that, because<br />

of the non - negativity of the z ij , it has to hold that z ij = 0 if i ≠ 1. Substituting i = 1 in (III. 93)<br />

yields<br />

W =<br />

∑N II<br />

j=1<br />

z 1j U 1 ⊗ V j<br />

= U 1 ⊗<br />

∑N II<br />

j=1<br />

z 1j V j = Tr II W ⊗ Tr I W, (III. 97)<br />

where the last step is in accordance with (III. 96).<br />

We conclude that only if, at least, one of the partial traces is pure, W is factorizable. □<br />

In the foregoing we saw that only if the state operator W of a composite system is factorizable, it<br />

can be uniquely defined. Contrary to classical physics, in quantum mechanics maximal knowledge of<br />

the state of the subsystems is in general not equivalent to maximal knowledge of the state of the entire

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