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Subsampling estimates of the Lasso distribution.

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2.3 A continous mapping <strong>the</strong>orem for argmin functionals 19<br />

and<br />

E ∗ (f( ˜X n )) = E ∗ (f(X n )) (2.3.0.7)<br />

for every f ∈ C b (B loc (R p )) and every n ∈ N. According to <strong>the</strong> same <strong>the</strong>orem, we can<br />

assume that <strong>the</strong> maps ˜X n take <strong>the</strong> form<br />

˜X n = X n ◦ φ n (2.3.0.8)<br />

for measurable perfect maps φ n : ˜Ω → Ω satisfying P n = ˜P ◦ φ −1<br />

n .<br />

Next, consider <strong>the</strong> maps ˜t n , ˜t and ˜α n obtained after composittion with φ n . Denote by ˜t<br />

<strong>the</strong> unique minimizer <strong>of</strong> ˜X, using a density argument, one can show that ˜t is measurable,<br />

hence has <strong>the</strong> same law as arg min(X). We need to prove that<br />

E ∗ f(t n ) − Ẽf(˜t) → 0 (2.3.0.9)<br />

for every f ∈ C b (R p ). By perfectness <strong>of</strong> <strong>the</strong> maps φ n , <strong>the</strong> difference is equal to<br />

Ẽ ∗ ( f(˜t n ) − f(˜t) ) ≤ Ẽ∗ (∣∣ f( ˜ t n ) − f(˜t) ∣ ∣ ) .<br />

To prove 2.3.0.9, first define for abitrary δ > 0<br />

{ }<br />

˜∆(δ) = inf ˜X(t) | ‖t − ˜t‖ > δ − ˜X(˜t).<br />

Then, for an arbitrary ε > 0, use tightness <strong>of</strong> {˜t n } n and uniqueness <strong>of</strong> ˜t to find R > 0,<br />

η > 0 satisfying :<br />

lim sup<br />

n→∞<br />

˜P ∗ ( ‖˜t n ‖ > R ) < ε<br />

and<br />

˜P<br />

(<br />

‖˜t‖ > R or ˜∆(δ)<br />

)<br />

< η < ε.<br />

The restriction <strong>of</strong> f on <strong>the</strong> closed ball B(0; R) is uniformly continuous by Heine-Borel’s<br />

Theorem. Since<br />

E ∗ (f(˜t n ) − f(˜t)) ≤ E ∗ (f(˜t n ) − f(˜t))1 { ‖˜t n ‖, ‖˜t‖ ≤ R } + 2 · 2‖f‖ |B(0;R) ε<br />

for n sufficiently large, it is sufficent to show that<br />

˜P ∗ ( ‖˜t n − ˜t‖ > δ; ‖˜t n ‖, ‖˜t‖ ≤ R ) → 0<br />

for each δ > 0.<br />

According to <strong>the</strong> Representation <strong>the</strong>orem, it holds that<br />

2 −R sup<br />

‖t‖≤R<br />

(<br />

‖ ˜X n (t) − ˜X(t)‖<br />

) ∗ (<br />

≤ d( ˜X ˜X)) ∗<br />

n , ≤ ε,<br />

for n sufficently large. Fur<strong>the</strong>rmore, it follows from<br />

˜X n (˜t) = ˜X n (t) + ˜X(t) − ˜X n (t)<br />

+ ˜X(˜t) − ˜X n (˜t)<br />

+ ˜X(˜t) − ˜X(t)

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