Impact of fuel supply impedance and fuel staging on gas turbine ...
Impact of fuel supply impedance and fuel staging on gas turbine ...
Impact of fuel supply impedance and fuel staging on gas turbine ...
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
3.2 Linear acoustic equati<strong>on</strong>s<br />
p ′<br />
ρ 0 c<br />
= f (ξ)+ g (η)= f (x− c t )+ g (x+ c t ). (3.21)<br />
The soluti<strong>on</strong> p ′ <str<strong>on</strong>g>of</str<strong>on</strong>g> the latter equati<strong>on</strong> is, in general, normalized by the characteristic<br />
<str<strong>on</strong>g>impedance</str<strong>on</strong>g> ρ 0 c. f <str<strong>on</strong>g>and</str<strong>on</strong>g> g are the so-called Riemann Invariants <str<strong>on</strong>g>and</str<strong>on</strong>g> are<br />
determined by boundary or initial c<strong>on</strong>diti<strong>on</strong>s. The Riemann Invariants represent<br />
physically waves, which are traveling with speed <str<strong>on</strong>g>of</str<strong>on</strong>g> sound c in the right or<br />
positive x-directi<strong>on</strong> (f ) or rather in the left or negative directi<strong>on</strong> (g ) as shown<br />
in Fig. 3.1.<br />
g<br />
f<br />
x<br />
Figure 3.1: Riemann Invariants f <str<strong>on</strong>g>and</str<strong>on</strong>g> g traveling in positive <str<strong>on</strong>g>and</str<strong>on</strong>g> negative x-<br />
directi<strong>on</strong><br />
The acoustic velocity u ′ can be obtained from the acoustic pressure p ′<br />
(Eqn. (3.21)) <str<strong>on</strong>g>and</str<strong>on</strong>g> the linearized momentum equati<strong>on</strong> (3.17):<br />
u ′ = f (x− c t )− g (x+ c t ). (3.22)<br />
Using Eqn. (3.21) <str<strong>on</strong>g>and</str<strong>on</strong>g> (3.22), the Riemann Invariants can be c<strong>on</strong>versely expressed<br />
in terms <str<strong>on</strong>g>of</str<strong>on</strong>g> p ′ <str<strong>on</strong>g>and</str<strong>on</strong>g> u ′ :<br />
f = 1 ( p<br />
′<br />
)<br />
2 ρ 0 c + u′ , (3.23)<br />
g = 1 ( p<br />
′<br />
)<br />
2 ρ 0 c − u′ . (3.24)<br />
49