Equipment for Rational Securing of Cargo on Railway ... - Vinnova

MariTerm AB 2004-01-30 jvgRASLA
a
t
= µ ⋅
( a + g)
v
µ ⋅ 2⋅n
⋅ F ⋅sinα
+
=
m
= 0.3⋅
( − 3 + 9.81)
0.3⋅
2⋅
2⋅
+
o
( 1000 + 700) ⋅sin 45
2
5000
= 2.3 m / s
The largest allowed transverse acceleration is 2.3 m/s 2 according to the calculations above.
When discarding from the vertical acceleration the following <strong>for</strong>mula is derived:
o
( 1000 + 700) ⋅ sin 45
2
µ ⋅ 2 ⋅ n ⋅ F ⋅sinα
0.3⋅
2 ⋅ 2 ⋅
a t
= µ ⋅ g +
= 0.3⋅9.81+
= 3.2 m / s
m
5000
The largest allowed transverse acceleration when the vertical acceleration is set to zero is 3.2
m/s 2 according to the calculations above.
5.11.3 Summery
The cargo can be exposed to accelerations <strong>of</strong> up to 2.3 m/s 2 in transverse direction when a
vertical acceleration <strong>of</strong> –3 m/s 2 acts and 3.2 m/s 2 when there is none. In this example the
largest allowed transverse acceleration <strong>for</strong> the specific guidelines reaches about 45% <strong>of</strong> the
general guidelines.
5.12 Steel sections
5.12.1 Purpose
The purpose is to analyse at what magnitude <strong>of</strong> acceleration a steel sections starts to slide
when secured according to UIC (RIV Appendix II, Section 2, Loading guidelines 1.6.1) the
steel sections can be placed directly on the wagon floor as long as they are lying flange side
down as shown below.
Steel section
Stanchion
112