Equipment for Rational Securing of Cargo on Railway ... - Vinnova

MariTerm AB 2004-01-30 jvgRASLA
5.12.3 Calculations
The steel sections will be treated as one package when calculating how large accelerations
they can be exerted to without sliding.
Equilibrium <strong>of</strong> <strong>for</strong>ces:
↑
→
R − m ⋅ g = m ⋅ a
F
f
= m ⋅ a
h
v
⇒
⇒
a
h
R = m ⋅
F
f
=
m
( a + g)
v
a h
Force
Acceleration
a v
Force <strong>of</strong> friction:
( a g)
F
f
= µ ⋅ R = µ ⋅ m ⋅
v
+
F f
R
mg
Largest horizontal acceleration that can act on the sections be<strong>for</strong>e they start to slide:
a
( a + g)
µ ⋅ m ⋅
v
= = µ ⋅
m
( a g)
h v
+
Transversal direction:
Largest allowed transverse acceleration when considering sliding. The vertical acceleration to
be calculated with according to UIC is –3 m/s 2
a
2
( a + g) = 0.3⋅( − 3 + 9.81) 2.0 m / s
t
= µ ⋅
v
=
When calculation is carried out without any vertical acceleration the largest allowable
transverse acceleration may is derived from the following <strong>for</strong>mula:
a t
= µ ⋅ g = 0.3⋅9.81
= 2.9 m / s
2
Longitudinal direction:
Largest allowed longitudinal acceleration when no vertical acceleration is acting.
a
2
( a + g) = 0.3⋅( 0 + 9.81) 2.9 m / s
l
= µ ⋅
v
=
5.12.4 Summery
The result is put together below were the largest allowed acceleration in respectively
transverse and longitudinal direction is shown. The vertical acceleration is taken into account
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