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The Real And Complex Number Systems

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Proof: Look at the Generalized Mean Value <strong>The</strong>orem, we try to get something from<br />

the equality.<br />

fa fbg a 2<br />

b ga gbf a 2<br />

b , *<br />

if fx, andgx satisfy following two conditions,<br />

(i) f x gx and g x fx<br />

and<br />

(ii) fa fb f a 2<br />

b ga gb g a 2<br />

b ,<br />

then we have the equality (*).<br />

5.14 Given a function f defined and having a finite derivative f in the half-open<br />

interval 0 x 1 and such that |f x| 1. Define a n f1/n for n 1, 2, 3, . . . , and<br />

show that lim n a n exists.<br />

Hint. Cauchy condition.<br />

Proof: Consider n m, and by Mean Value <strong>The</strong>orem,<br />

|a n a m| |f1/n f1/m| |f p| 1 n m 1 1 n m<br />

1<br />

then a n is a Cauchy sequence since 1/n is a Cauchy sequence. Hence, we know that<br />

lim n a n exists.<br />

5.15 Assume that f has a finite derivative at each point of the open interval a, b.<br />

Assume also that lim xc f x exists and is finite for some interior point c. Prove that the<br />

value of this limit must be f c.<br />

Proof: It can be proved by Exercise 5.16; we omit it.<br />

5.16 Let f be continuous on a, b with a finite derivative f everywhere in a, b,<br />

expect possibly at c. If lim xc f x exists and has the value A, show that f c must also<br />

exist and has the value A.<br />

Proof: Consider, for x c,<br />

fx fc<br />

x c f where x, c or c, x by Mean Value <strong>The</strong>orem, *<br />

since lim xc f x exists, given 0, there is a 0 such that as x c , c c,<br />

we have<br />

A f x A .<br />

So, if we choose x c , c c in (*), we then have<br />

fx fc<br />

A x c f A .<br />

That is, f c exists and equals A.<br />

Remark: (1) Here is another proof by L-Hospital Rule. Since it is so obvious that we<br />

omit the proof.<br />

(2) We should be noted that Exercise 5.16 implies Exercise 5.15. Both methods<br />

mentioned in Exercise 5.16 are suitable for Exercise 5.15.<br />

5.17 Let f be continuous on 0, 1, f0 0, f x defined for each x in 0, 1. Prove<br />

that if f is an increasing function on 0, 1, then so is too is the function g defined by the<br />

equation gx fx/x.<br />

Proof: Sincef is an increasing function on 0, 1, we know that, for any x 0, 1

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