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The Real And Complex Number Systems

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So,<br />

<br />

(b) n2<br />

1 1<br />

n 2 −1<br />

Proof: Consider<br />

we have<br />

So,<br />

<br />

<br />

n2<br />

1 − 1<br />

2 n − 2<br />

1<br />

2 ∑ .<br />

n1 nn1<br />

1 1<br />

n 2 − 1 n 2<br />

n 2 − 1 <br />

n<br />

<br />

k2<br />

<br />

<br />

n2<br />

1 1<br />

k 2 − 1<br />

1 1<br />

n 2 − 1<br />

<br />

2 ∑ 2 −n<br />

n1<br />

2.<br />

nn<br />

n − 1n 1 ,<br />

n<br />

<br />

kk<br />

k − 1k 1<br />

k2<br />

2 n<br />

n 1<br />

2 1 − 1<br />

n<br />

2 ∑<br />

k1<br />

<br />

2 ∑<br />

n1<br />

2.<br />

n 1<br />

1<br />

kk 1 .<br />

1<br />

nn 1<br />

8.42 Determine all real x for which the product <br />

n1<br />

cosx/2 n converges and find the<br />

value of the product when it does converge.<br />

Proof: Ifx ≠ m, wherem ∈ Z, thensin x<br />

n<br />

<br />

k1<br />

cosx/2 k 2n sin x<br />

2 n<br />

2 n sin x<br />

n<br />

<br />

2 n k1<br />

2 n ≠ 0 for all n ∈ N. Hence,<br />

cosx/2 k <br />

sin x<br />

2 n sin x → sin x x .<br />

2 n<br />

If x m, wherem ∈ Z. <strong>The</strong>n as m 0, it is clear that the product converges to 1. So,<br />

we consider m ≠ 0 as follows. Since x m, choosing n large enough, i.e., as n ≥ N so<br />

that sin x ≠ 0. Hence,<br />

2 n<br />

and note that<br />

Hence,<br />

n<br />

<br />

k1<br />

N−1<br />

cosx/2 k <br />

k1<br />

lim n→<br />

n<br />

cosx/2 k cosx/2 k <br />

kN<br />

N−1<br />

cosx/2 k sinx/2<br />

<br />

N−1 <br />

2 n−N1 sinx/2 n <br />

k1<br />

sinx/2 N−1 <br />

2 n−N1 sinx/2 n sinx/2N−1 <br />

x/2 N−1 .<br />

<br />

cosx/2 k sinx/2N−1 N−1<br />

<br />

cosx/2<br />

x/2 N−1 k .<br />

k1<br />

k1

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