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The Real And Complex Number Systems

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1.39 State and prove a theorem analogous to <strong>The</strong>orem 1.54, expressing<br />

Log (z 1 /z 2 ) in terms of Log (z 1 ) and Log (z 2 ) .<br />

Proof: Write z 1 = r 1 e i arg(z 1) and z 2 = r 2 e i arg(z 2) , then<br />

Hence,<br />

∣ Log (z 1 /z 2 ) = log<br />

z 1 ∣∣∣<br />

∣ + i arg<br />

z 2<br />

z 1<br />

z 2<br />

= r 1<br />

r 2<br />

e i[arg(z 1)−arg(z 2 )] .<br />

(<br />

z1<br />

z 2<br />

)<br />

= log |z 1 | − log |z 2 | + i [arg (z 1 ) − arg (z 2 ) + 2πn (z 1 , z 2 )] by xercise 1.38<br />

= Log (z 1 ) − Log (z 2 ) + i2πn (z 1 , z 2 ) .<br />

1.40 Prove that the nth roots of 1 (also called the nth roots of unity)<br />

are given by α, α 2 , ..., α n , where α = e 2πi/n , and show that the roots ≠ 1<br />

satisfy the equation<br />

1 + x + x 2 + ... + x n−1 = 0.<br />

Proof: By <strong>The</strong>orem 1.51, we know that the roots of 1 are given by<br />

α, α 2 , ..., α n , where α = e 2πi/n . In addition, since<br />

which implies that<br />

x n = 1 ⇒ (x − 1) ( 1 + x + x 2 + ... + x n−1) = 0<br />

1 + x + x 2 + ... + x n−1 = 0 if x ≠ 1.<br />

So, all roots except 1 satisfy the equation<br />

1 + x + x 2 + ... + x n−1 = 0.<br />

1.41 (a) Prove that |z i | < e π for all complex z ≠ 0.<br />

Proof: Since<br />

z i = e iLog(z) = e − arg(z)+i log|z| ,<br />

27

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