06.01.2015 Views

The Real And Complex Number Systems

The Real And Complex Number Systems

The Real And Complex Number Systems

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

point of M. Sincx is arbitrary, we know that every point of M is interior. So, M is open.<br />

Let x be an adherent point of M, it is clearly x M since we consider all points lie in<br />

M. Hence, M contains its all adherent points. It implies that M is closed.<br />

Remark: <strong>The</strong> reader should regard the statement as a common sense.<br />

3.27 Consider the following two metrics in R n :<br />

in<br />

d 1 x, y max 1in |x i y i |, d 2 x, y |xi i1<br />

y i |.<br />

In each of the following metric spaces prove that the ball Ba; r has the geometric<br />

appearance indicated:<br />

(a) In R 2 , d 1 , a square with sides parallel to the coordinate axes.<br />

Solution: It suffices to consider the case B0, 0,1. Letx x 1 , x 2 B0, 0,1,<br />

then we have<br />

|x 1 | 1, and |x 2 | 1.<br />

So, it means that the ball B0, 0,1 is a square with sides lying on the coordinate axes.<br />

Hence, we know that Ba; r is a square with sides parallel to the coordinate axes.<br />

(b) In R 2 , d 2 , a square with diagonals parallel to the axes.<br />

Solution: It suffices to consider the case B0, 0,1. Letx x 1 , x 2 B0, 0,1,<br />

then we have<br />

|x 1 x 2 | 1.<br />

So, it means that the ball B0, 0,1 is a square with diagonals lying on the coordinate<br />

axes. Hence, we know that Ba; r is a square with diagonals parallel to the coordinate<br />

axes.<br />

(c) A cube in R 3 , d 1 .<br />

Solution:It suffices to consider the case B0, 0, 0,1. Let<br />

x x 1 , x 2 , x 3 B0, 0, 0,1, then we have<br />

|x 1 | 1, |x 2 | 1, and |x 3 | 1.<br />

So, it means that the ball B0, 0, 0,1 is a cube with length 2. Hence, we know that<br />

Ba; r is a cube with length 2a.<br />

(d) An octahedron in R 3 , d 2 .<br />

Solution: It suffices to consider the case B0, 0, 0,1. Let<br />

x x 1 , x 2 , x 3 B0, 0, 0,1, then we have<br />

|x 1 x 2 x 3 | 1.<br />

It means that the ball B0, 0, 0,1 is an octahedron. Hence, Ba; r is an octahedron.<br />

Remark: <strong>The</strong> exercise tells us one thing that Ba; r may not be an n ball if we<br />

consider some different matrices.<br />

3.28 Let d 1 and d 2 be the metrics of Exercise 3.27 and let x y denote the usual<br />

Euclidean metric. Prove that the following inequalities for all x and y in R n :<br />

d 1 x, y x y d 2 x, y and d 2 x, y n x y nd 1 x, y.<br />

Proof: List the definitions of the three metrics, and compare with them as follows.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!