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The Real And Complex Number Systems

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fx y fx fy <br />

1 x y 1 x 1 y 1 Q if x y Q c ,<br />

x y 1 x 1 y 2 Q if x y Q.<br />

Remark: Here is an interesting question about functions. Let f : R 0, 1 R. Iff<br />

satisfies that<br />

fx f x 1<br />

x 1 x,<br />

then fx x3 x 2 1<br />

. 2xx1<br />

Proof: Let x x1<br />

x , then we have 2 x 1<br />

x1 ,and3 x x. So,<br />

fx f x 1<br />

x fx fx 1 x *<br />

which implies that<br />

fx f 2 x 1 x **<br />

and<br />

f 2 x f 3 x f 2 x fx 1 2 x. ***<br />

So, by (*), (**), and (***), we finally have<br />

fx 1 2 1 x x 2 x<br />

x3 x 2 1<br />

2xx 1 .<br />

4.18 Let f be defined on R and assume that there exists at least one x 0 in R at which f<br />

is continuous. Suppose also that, for every x and y in R, f satisfies the equation<br />

fx y fx fy.<br />

Prove that there exists a constant a such that fx ax for all x.<br />

Proof: Let f be defined on R and assume that there exists at least one x 0 in R at which f<br />

is continuous. Suppose also that, for every x and y in R, f satisfies the equation<br />

fx y fx fy.<br />

Prove that there exists a constant a such that fx ax for all x.<br />

Proof: Suppose that f is continuous at x 0 , and given any r R. Since<br />

fx y fx fy for all x, then<br />

fx fy x 0 fr, wherey x r x 0 .<br />

Note that y x 0 x r, then<br />

lim xr<br />

fx lim xr<br />

fy x 0 fr<br />

yx0<br />

lim fy x 0 fr<br />

fr since f is continuous at x 0 .<br />

So, f is continuous at r. Sincer is arbitrary, we have f is continuous on R. Definef1 a,<br />

andthensincefx y fx fy, wehave<br />

f1 f 1 m .. m 1 mtimes<br />

mf<br />

1 m<br />

f 1 m f1<br />

m *

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