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The Real And Complex Number Systems

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So, we have<br />

Partial derivatives<br />

fb fa b af x.<br />

5.33 Consider the function f defined on R 2 by the following formulas:<br />

xy<br />

fx, y if x, y 0, 0 f0, 0 0.<br />

x 2 y2 Prove that the partial derivatives D 1 fx, y and D 2 fx, y exist for every x, y in R 2 and<br />

evaluate these derivatives explicitly in terms of x and y. Also, show that f is not continuous<br />

at 0, 0.<br />

Proof: It is clear that for all x, y 0, 0, wehave<br />

D 1 fx, y y y2 x 2<br />

x 2 y 2 and D 2fx, y x x2 y 2<br />

2 x 2 y 2 . 2<br />

For x, y 0, 0, wehave<br />

fx,0 f0, 0<br />

D 1 f0, 0 lim<br />

0.<br />

x0 x 0<br />

Similarly, we have<br />

D 2 f0, 0 0.<br />

In addition, let y x and y 2x, wehave<br />

limfx, x 1/2 limfx,2x 2/5.<br />

x0 x0<br />

Hence, f is not continuous at 0, 0.<br />

Remark: <strong>The</strong> existence of all partial derivatives does not make sure the continuity of f.<br />

<strong>The</strong> trouble with partial derivatives is that they treat a function of several variables as a<br />

function of one variable at a time.<br />

5.34 Let f be defined on R 2 as follows:<br />

fx, y y x2 y 2<br />

if x,,y 0, 0, f0, 0 0.<br />

x 2 y2 Compute the first- and second-order partial derivatives of f at the origin, when they exist.<br />

Proof: For x, y 0, 0, it is clear that we have<br />

4xy<br />

D 1 fx, y <br />

3<br />

x 2 y 2 and D 2fx, y x4 4x 2 y 2 y 4<br />

2 x 2 y 2 2<br />

and for x, y 0, 0, wehave<br />

fx,0 f0, 0<br />

f0, y f0, 0<br />

D 1 f0, 0 lim<br />

0, D<br />

x0 x 0<br />

2 f0, 0 lim<br />

1.<br />

y0 y 0<br />

Hence,<br />

and<br />

D 1,2 f0, 0 lim<br />

x0<br />

D 1 fx,0 D 1 f0, 0<br />

0,<br />

x 0<br />

D 2 fx,0 D 2 f0, 0<br />

lim 2<br />

x 0<br />

x0 x does not exist,<br />

D 1 f0, y D 1 f0, 0<br />

0,<br />

y 0<br />

D 1,1 f0, 0 lim<br />

x0<br />

D 2,1 f0, 0 lim<br />

y0

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