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The Real And Complex Number Systems

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(Lemma) If {a n } and {b n } are two sequences of complex numbers, define<br />

A n =<br />

n∑<br />

a k .<br />

k=1<br />

<strong>The</strong>n we have the identity<br />

n∑<br />

n∑<br />

a k b k = A n b n+1 − A k (b k+1 − b k )<br />

(i)<br />

k=1<br />

= A n b 1 +<br />

k=1<br />

n∑<br />

(A n − A k ) (b k+1 − b k ) . (ii)<br />

k=1<br />

Proof: <strong>The</strong> identity (i) comes from <strong>The</strong>orem 8.27. In order to show<br />

(ii), it suffices to consider<br />

b n+1 = b 1 +<br />

n∑<br />

b k+1 − b k .<br />

k=1<br />

9.14 Let f n (x) = x/ (1 + nx 2 ) if x ∈ R, n = 1, 2, ... Find the limit function<br />

f of the sequence {f n } and the limit function g of the sequence {f ′ n} .<br />

(a) Prove that f ′ (x) exists for every x but that f ′ (0) ≠ g (0) . For what<br />

values of x is f ′ (x) = g (x)<br />

Proof: It is easy to show that the limit function f = 0, and by f ′ n (x) =<br />

1−nx 2<br />

(1+nx 2 ) 2 , we have<br />

{ 1 if x = 0<br />

lim f n ′ (x) = g (x) =<br />

n→∞ 0 if x ≠ 0 .<br />

Hence, f ′ (x) exists for every x and f ′ (0) = 0 ≠ g (0) = 1. In addition, it is<br />

clear that as x ≠ 0, we have f ′ (x) = g (x) .<br />

(b) In what subintervals of R does f n → f uniformly<br />

Proof: Note that<br />

1 + nx 2<br />

2<br />

≥ √ n |x|<br />

13

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