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The Real And Complex Number Systems

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n<br />

c n ∑ a k b n−k .<br />

k0<br />

Proof: By<strong>The</strong>orem 8.44 and <strong>The</strong>orem 8.13, it is clear.<br />

Remark: We can use Mertens’ <strong>The</strong>orem, thenitisclear.<br />

8.34 Aseriesoftheform∑ <br />

n1<br />

a n /n s is called a Dirichlet series. Given two absolutely<br />

convergent Dirichlet series, say ∑ <br />

n1<br />

a n /n s and ∑ <br />

n1<br />

b n /n s , having sums As and Bs,<br />

respectively, show that ∑ n1<br />

c n /n s AsBs, wherec n ∑ d|n<br />

a d b n/d .<br />

Proof: By<strong>The</strong>orem 8.44 and <strong>The</strong>orem 8.13, wehave<br />

<br />

∑<br />

n1<br />

a n /n s<br />

<br />

∑<br />

n1<br />

<br />

b n /n s ∑<br />

n1<br />

where<br />

C n ∑ a d d −s b n/d n/d −s<br />

d|n<br />

n −s ∑ a d b n/d<br />

d|n<br />

c n /n s .<br />

So,wehaveprovedit.<br />

8.35 s ∑ <br />

n1<br />

1/n s , s 1, show that 2 s ∑ <br />

n1<br />

dn/n s ,wheredn is the<br />

number of positive divisors of n (including 1 and n).<br />

Proof: ItisclearbyExercise 8.34. So, we omit the proof.<br />

Ces’aro summability<br />

8.36 Show that each of the following series has C,1 sum 0 :<br />

(a) 1 − 1 − 1 1 1 − 1 − 1 1 1 −−.<br />

Proof: It is clear that |s 1 ...s n| ≤ 1 for all n, wheres n means that the nth partial sum<br />

of given series. So,<br />

s 1 ...s n<br />

n ≤ 1 n<br />

which implies that the given series has C,1 sum 0.<br />

(b) 1 − 1 1 1 − 1 1 1 − 1 − .<br />

2 2 2 2 2<br />

Proof: It is clear that |s 1 ...s n| ≤ 1 for all n, wheres 2<br />

n means that the nth partial<br />

sum of given series. So,<br />

s 1 ...s n<br />

n ≤<br />

2n<br />

1<br />

which implies that the given series has C,1 sum 0.<br />

(c) cos x cos3x cos5x (x real, x ≠ m).<br />

Proof: Lets n cosx ... cos2n − 1x, then<br />

C n

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