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The Real And Complex Number Systems

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sin 2s1 k sin 2 ksin k 2s−1<br />

sin 2 k<br />

s<br />

∑ a j sin2j − 1k<br />

j1<br />

s<br />

∑ a j sin 2 k sin2j − 1k<br />

j1<br />

s<br />

∑ a j<br />

j1<br />

1 2<br />

1 2<br />

s<br />

∑<br />

j1<br />

1 − cos2k<br />

2<br />

sin2j − 1k<br />

by induction hypothesis<br />

s<br />

a j sin2j − 1k − ∑ a j cos2k sin2j − 1k<br />

j1<br />

s<br />

∑ a j sin2j − 1k − 1 2 ∑ s<br />

j1<br />

j1<br />

a j sin2j 1k sin2j − 3k<br />

which is a linear combination of sink,...,sin2s 1k. Hence, we have proved the claim<br />

by Mathematical Induction.<br />

Remark: By the same argument, the series<br />

n<br />

∑<br />

k1<br />

cos 2p−1 k<br />

is also bounded, i.e., there exists a positive number Mp such that<br />

n<br />

(6) Define ∑ k1<br />

n<br />

∑<br />

k1<br />

|cos 2p−1 k| ≤ Mp.<br />

sinkx<br />

: F<br />

k n x, then F n x is boundedly convergent on R.<br />

Proof: SinceF n x is a periodic function with period 2, andF n x is an odd function.<br />

So, it suffices to consider F n x is defined on 0, . In addition, F n 0 0 for all n.<br />

Hence, the domain I that we consider is 0, . Note that sinkx x<br />

cosktdt. So,<br />

0<br />

n<br />

F n x ∑<br />

k1<br />

<br />

0<br />

x<br />

∑<br />

k1<br />

<br />

0<br />

x<br />

<br />

0<br />

x<br />

sin kx<br />

k<br />

n<br />

cosktdt<br />

sinn 1 t − sin 1 t<br />

2 2<br />

2sin 1 t dt<br />

2<br />

sinn 1 2 t<br />

t<br />

dt <br />

0<br />

x<br />

1<br />

2sin t 2<br />

− 1 t<br />

k<br />

sin n 1 2 t dt − x 2<br />

which implies that<br />

<br />

0<br />

n 1 2<br />

x sin t<br />

t<br />

|F n x| ≤ <br />

0<br />

n 1 2 x sin t<br />

t<br />

dt <br />

0<br />

x t − 2sin t 2<br />

2t sin t 2<br />

dt <br />

0<br />

x t − 2sin t 2<br />

2t sin t 2<br />

sin n 1 2 t dt − x 2<br />

sin n 1 2 t dt 2 .

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