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The Real And Complex Number Systems

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9.38 For each real t, define f t (x) = xe xt / (e x − 1) if x ∈ R, x ≠ 0,<br />

f t (0) = 1.<br />

(a) Show that there is a disk B (0; δ) in which f t is represented by a power<br />

series in x.<br />

Proof: First, we note that ex −1<br />

= ∑ ∞ x n<br />

x n=0<br />

:= p (x) , then p (0) = 1 ≠<br />

(n+1)!<br />

0. So, by <strong>The</strong>orem 9. 26, there exists a disk B (0; δ) in which the reciprocal<br />

of p has a power series exapnsion of the form<br />

∞<br />

1<br />

p (x) = ∑<br />

q n x n .<br />

So, as x ∈ B (0; δ) by <strong>The</strong>orem 9.24.<br />

n=0<br />

f t (x) = xe xt / (e x − 1)<br />

( ∞<br />

) (<br />

∑ (xt) n ∞<br />

)<br />

∑ x n<br />

=<br />

n! (n + 1)!<br />

n=0<br />

n=0<br />

∞∑<br />

= r n (t) x n .<br />

n=0<br />

(b) Define P 0 (t) , P 1 (t) , P 2 (t) , ..., by the equation<br />

and use the identity<br />

f t (x) =<br />

n=0<br />

∞∑<br />

n=0<br />

P n (t) xn<br />

, if x ∈ B (0; δ) ,<br />

n!<br />

∞∑<br />

P n (t) xn<br />

n! = ∑ ∞ etx P n (0) xn<br />

n!<br />

to prove that P n (t) = ∑ n<br />

k=0 (n k ) P k (0) t n−k .<br />

Proof: Since<br />

f t (x) =<br />

∞∑<br />

n=0<br />

n=0<br />

P n (t) xn<br />

n! = etx x<br />

e x − 1 ,<br />

35

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