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The Real And Complex Number Systems

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and<br />

vx, y e 1 log|z| 2 arg z<br />

sin 2 log|z| 1 arg z<br />

e 1 logx 2 y 2 1/2 2 argxiy<br />

sin 2 logx 2 y 2 1/2 1 argx iy .<br />

(ii) Show that u and v satisfy the Cauchy -Riemanns equation for the following values<br />

of z :Allz in (a), (b), (g); no z in (c), (d), (e); all z except real z 0in(f),(h).<br />

So,<br />

and<br />

Proof: (a)sinz u iv, where<br />

ux, y ey e y sin x<br />

2<br />

u x v y ey e y cosx<br />

2<br />

and vx, y ey e y cosx<br />

2<br />

for all z x iy<br />

u y v x ey e y sin x<br />

for all z x iy.<br />

2<br />

(b) cos z u iv, where<br />

ux, y ey e y cosx<br />

and vx, y ey e y sin x<br />

2<br />

2<br />

So,<br />

u x v y ey e y sin x<br />

for all z x iy.<br />

2<br />

and<br />

u y v x ey e y cosx<br />

for all z x iy.<br />

2<br />

(c) |z| u iv, where<br />

ux, y x 2 y 2 1/2 and vx, y 0.<br />

So,<br />

u x xx 2 y 2 1/2 v y 0ifx 0, y 0.<br />

and<br />

u y yx 2 y 2 1/2 v x 0ifx 0, y 0.<br />

So, we know that no z makes Cauchy-Riemann equations hold.<br />

(d) z u iv, where<br />

ux, y x and vx, y y.<br />

So,<br />

u x 1 1 v y .<br />

So, we know that no z makes Cauchy-Riemann equations hold.<br />

(e) arg z u iv, where<br />

ux, y argx 2 y 2 1/2 and vx, y 0.<br />

Note that<br />

.<br />

.

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