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Taylor - Theoretic Arithmetic.pdf - Platonic Philosophy

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agreeably to the form of the evenly-odd number. Thus in the<br />

number 24, the quantity of the part is even, being denominated<br />

from the even number. For the fourth part of it is 6, the<br />

second part is 12, the sixth part is 4, and the twelfth part is 2,<br />

which appellations of parts are not discordant from parity of<br />

quantity. The parts however 8, 3, and 1 do not correspond in<br />

denomination to the quantities; for 8 is the third part, 3 is the<br />

eighth part, and 1 is the twentyfourth part. Hence in this instance,<br />

when the denominations are even, the quantities are<br />

found to be odd, and when the quantities are even, the denominations<br />

are odd.<br />

But these numbers are produced in such a way as to designate<br />

their essence and nature even in their very generation;<br />

for they are the progeny of the evenly-even, and the evenlyodd<br />

numbers. For the evenly-odd are produced, as we have<br />

shown from the series of odd numbers; but the evenly-even<br />

from the duple progression. Let all the numbers therefore,<br />

that are naturally odd, be disposed in order, and under these<br />

all the numbers in a duple progression beginning from 4 as<br />

follows :<br />

3 5 7 9 11 13 15 17 19 etc.<br />

4 8 16 32 64 128 256 512 1024 etc.<br />

If therefore the first number in one series, is multiplied by<br />

the first in the other, viz. if 3 is multiplied by 4, or if the same<br />

first is multiplied by the second number in the second series,<br />

i.e. if 3 is multiplied by 8, or the first by the third, i.e. 3 by 16,<br />

and so on as far as to the last term; or if tht: second tern1 in<br />

the first series is multiplied by the first, or second or third, or<br />

in short, by any term in the second series; or the third term in<br />

the first series, by any term in the second, and so of the fourth,<br />

fifth etc. terms in the first series, all the numbers thus produced<br />

will be unevenly-even. Thus 3 )< 4=12, 5 )

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