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Wireless Network Design: Optimization Models and Solution ...

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138 Jeff Kennington, Jason Kratz, <strong>and</strong> Gheorghe Spiride<br />

zs 2m ≤ 1 − ws 1 ∀m ∈ M,s1,s2 ∈ S|s1 �= s2 <strong>and</strong> γs 1 > γs 2 (6.4)<br />

The next |M| constraints ensure that every MD is assigned to some AP.<br />

∑ zsm = 1<br />

s∈S<br />

∀m ∈ M (6.5)<br />

The next set of constraints force xs 1s 2 f to assume the value 1 if <strong>and</strong> only if both AP<br />

s1 <strong>and</strong> s2 are installed <strong>and</strong> assigned frequency f .<br />

xs 1s 2 f ≤ ys 1 f ∀s1,s2 ∈ S, f ∈ F|s1 < s2 (6.6)<br />

xs 1s 2 f ≤ ys 2 f ∀s1,s2 ∈ S, f ∈ F|s1 < s2 (6.7)<br />

xs 1s 2 f ≥ ys 1 f + ys 2 f − 1 ∀s1,s2 ∈ S, f ∈ F|s1 < s2 (6.8)<br />

Suppose MD m1 is associated with AP s1. The throughput for m1 is related to<br />

the signal-to-noise ratio at m1, as well as the total number of MDs associated with<br />

s1 (see [16]). The signal strength at m1 is given by Ps1 γs1m1 <strong>and</strong> the noise at m1 is<br />

given by ∑s 2∈S�{s 1} Ps 1 γs 1m 1 + Nm 1 . Let tsm denote the downlink signal strength at m<br />

for the s − m association. Then<br />

tsm = Psγsmzsm ∀s ∈ S,m ∈ M (6.9)<br />

If m is not associated with s then both zsm <strong>and</strong> tsm will be zero. Let usm denote the<br />

interference at m experienced by the s − m association. Then<br />

usm = ∑ ∑ Ps2<br />

s2∈S�{s}:s

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